CodeForces776-A.Serial Killer-string】的更多相关文章

[题目链接]:http://codeforces.com/contest/776/problem/A [题意] 这个杀手每天会除掉一个人; 这个杀手每天都有两个目标; 给你它杀人的日志,以及这个人被杀掉之后替代的人是谁; 让你输出每天杀人的两个目标; [题解] /* 可以边读边操作; s1记录第一个人,s2记录第二个人; 输入a b两个字符串 cout << s1 << ' '<<s2<<endl; if (a==s1) { s1 = b; } else {…
A Serial Killer time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers o…
A Serial Killer time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers o…
Linux/drivers/usb/serial/ftdi_sio.h /* 2 * Driver definitions for the FTDI USB Single Port Serial Converter - 3 * known as FTDI_SIO (Serial Input/Output application of the chipset) 4 * 5 * For USB vendor/product IDs (VID/PID), please see ftdi_sio_ids…
串口波特率的设置:通常我们使用Serial.begin(speed)来完成串口的初始化,这种方式,只能配置串口的波特率. 使用Serial.begin(speed, config)可以配置数据位.校验位.停止位等.例如Serial.begin(9600,SERIAL_8E2)是将串口波特率设为9600,数据位8,偶校验,停止位2. 9600 串口波特率 SERIAL_8E2 8:8位 E:偶校验 2:停止位 config可用配置如下: 1: 少用 if (Serial)的用法:串口打开为真,串口…
前四题比较水,E我看出是欧拉函数傻逼题,但我傻逼不会,百度了下开始学,最后在加时的时候A掉了 AC:ABCDE Rank:182 Rating:2193+34->2227 终于橙了,不知道能待几天 A.A Serial Killer 题目大意:一开始给你两个字符串,每次给你当前两个串中的一个和一个新的串,用新的串换掉旧的,每次输出当前的串.(次数<=1000) 思路:二逼题 #include<iostream> using namespace std; int main() { s…
A. A Serial Killer time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his power…
Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers of deduction, he came to know that the killer has a strategy for selecting his next victim. The killer starts with two potentia…
ICM Technex 2017 and Codeforces Round #400 (Div. 1 +Div.2,combined) A. A Serial Killer 谜一样的题意:每天从两个人里面选一个人杀掉然后另一个人替补,已知每天要杀掉的和代替者和第一天候选的两个人,求每天候选的两个人的名字,顺序任意. int main() { string a,b,c,d; int n; cin>>a>>b; cin>>n; cout<<a<<&q…
题目戳这里 A.A Serial Killer 题目描述似乎很恶心,结合样例和样例解释猜测的题意 使用C++11的auto可以来一手骚操作 #include <bits/stdc++.h> using namespace std; int n; ]; map <string, int> p; int main() { cin >> s[] >> s[]; p[s[]] = p[s[]] = ; cin >> n; cout << s[…