We are given head, the head node of a linked list containing unique integer values. We are also given the list G, a subset of the values in the linked list. Return the number of connected components in G, where two values are connected if they appear…
题目标签:Linked List 题目给了我们一组 linked list, 和一组 G, 让我们找到 G 在 linked list 里有多少组相连的部分. 把G 存入 hashset,遍历 linked list, 利用 hashset 来检查目前的点 和 下一个点 是否在G 里面. 如果目前的点在G里面,下一个点不在,说明这里断开了.具体看code. Java Solution: Runtime:  7 ms, faster than 81 % Memory Usage: 40 MB, l…
817. 链表组件 给定一个链表(链表结点包含一个整型值)的头结点 head. 同时给定列表 G,该列表是上述链表中整型值的一个子集. 返回列表 G 中组件的个数,这里对组件的定义为:链表中一段最长连续结点的值(该值必须在列表 G 中)构成的集合. 示例 1: 输入: head: 0->1->2->3 G = [0, 1, 3] 输出: 2 解释: 链表中,0 和 1 是相连接的,且 G 中不包含 2,所以 [0, 1] 是 G 的一个组件,同理 [3] 也是一个组件,故返回 2. 示例…
Question 817. Linked List Components Solution 题目大意:给一个链表和该链表元素组成的一个子数组,求子数组在链表中组成多少个片段,每个片段中可有多个连续的元素 思路:构造一个set用来存储子数组元素用于判断是否存在,遍历链表,如果当前元素不存在而下一个元素存在就表示一个片段的开始了,遍历前先判断首元素是否存在 Java实现: public int numComponents(ListNode head, int[] G) { Set<Integer>…
2.3 Implement an algorithm to delete a node in the middle of a singly linked list, given only access to that node.EXAMPLEInput: the node c from the linked list a->b->c->d->eResult: nothing is returned, but the new linked list looks like a- >…
​给定一个链表,旋转链表,将链表每个节点向右移动 k 个位置,其中 k 是非负数. Given a linked list, rotate the list to the right by k places, where k is non-negative. 示例 1: 输入: 1->2->3->4->5->NULL, k = 2 输出: 4->5->1->2->3->NULL 解释: 向右旋转 1 步: 5->1->2->3-…
Linked List Sorting (链表)   A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you ar…
Linked List Cycle II Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up: Can you solve it without using extra space? 和问题一Linked List Cycle几乎一样.如果用我的之前的解法的话,可以很小修改就可以实现这道算法了.但是如果问题一用优化了的解法的话,那么就不适…
一.      Spring Auto Scanning Components —— 自动扫描组件 1.      Declares Components Manually——手动配置component 2.      Auto Components Scanning——自动扫描组件 3.      Custom auto scan component name——自定义扫描组件名称 4.      Auto Components Scan Antotation Types——自动扫描组件的注释…
LeetCode:删除排序链表中的重复元素[83] 题目描述 给定一个排序链表,删除所有重复的元素,使得每个元素只出现一次. 示例 1: 输入: 1->1->2 输出: 1->2 示例 2: 输入: 1->1->2->3->3 输出: 1->2->3 题目分析 这道题是链表中的双指针问题,常规思路是定义两个指针,一个slow,一个fast,首先题目已经说明是排序数组,所以所有重复元素都是挨着的,这样子的话我们就要考虑删除多个元素的问题. Java题解…
给定一个排序链表,删除所有含有重复数字的节点,只保留原始链表中 没有重复出现 的数字. 思路和上一题类似(参考 力扣(LeetCode)删除排序链表中的重复元素 个人题解)) 只不过这里需要用到一个前置节点来排除第一个节点就是重复元素的特例. 同样是使用快慢针解决问题.不再详细叙述. 代码如下: class Solution { public ListNode deleteDuplicates(ListNode head) { ListNode ret = new ListNode(0); re…
LeetCode刷题总结-链表 一.链表     链表分为单向链表.单向循环链表和双向链表,一下以单向链表为例实现单向链表的节点实现和单链表的基本操作. 单向链表 单向链表也叫单链表,是链表中最简单的一种形式,它的每个节点包含两个域,一个信息域(元素域)和一个链接域.这个链接指向链表中的下一个节点,而最后一个节点的链接域则指向一个空值. 表元素域elem用来存放具体的数据: 链接域next用来存放下一个节点的位置(python中的标识): 变量p指向链表的头节点(首节点)的位置,从p出发能找到表…
LeetCode & linked list bug add-two-numbers shit test /** * Definition for singly-linked list. * function ListNode(val) { * this.val = val; * this.next = null; * } */ /** * @param {ListNode} l1 * @param {ListNode} l2 * @return {ListNode} */ var addTwo…
Leetcode算法系列(链表)之删除链表倒数第N个节点 难度:中等给定一个链表,删除链表的倒数第 n 个节点,并且返回链表的头结点.示例:给定一个链表: 1->2->3->4->5, 和 n = 2.当删除了倒数第二个节点后,链表变为 1->2->3->5.说明:给定的 n 保证是有效的.链接:https://leetcode-cn.com/problems/remove-nth-node-from-end-of-list Python实现 # Definiti…
Leetcode算法系列(链表)之两数相加 难度:中等给出两个 非空 的链表用来表示两个非负的整数.其中,它们各自的位数是按照 逆序 的方式存储的,并且它们的每个节点只能存储 一位 数字.如果,我们将这两个数相加起来,则会返回一个新的链表来表示它们的和.您可以假设除了数字 0 之外,这两个数都不会以 0 开头.示例:输入:(2 -> 4 -> 3) + (5 -> 6 -> 4)输出:7 -> 0 -> 8原因:342 + 465 = 807 链接:https://le…
We are given head, the head node of a linked list containing unique integer values. We are also given the list G, a subset of the values in the linked list. Return the number of connected components in G, where two values are connected if they appear…
We are given head, the head node of a linked list containing unique integer values. We are also given the list G, a subset of the values in the linked list. Return the number of connected components in G, where two values are connected if they appear…
https://leetcode.com/problems/linked-list-components/ We are given head, the head node of a linked list containing unique integer values. We are also given the list G, a subset of the values in the linked list. Return the number of connected componen…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/linked-list-components/description/ 题目描述 We are given head, the head node of a linked list containing unique integer values. We are also g…
Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen. Follow up: What if the linked list is extremely large and its length is unknown to you? Could you solve this effi…
Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. You should try to do it in place. The program should run in O(1) space complexi…
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 ->…
Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 之前做到Reverse Linked List II 倒置链表之二的时候我还纳闷怎么只有二没有一呢,原来真是忘了啊,现在才加上,这道题跟之前那道比起来简单不少,题目为了增加些许难度,让我们分别用…
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up: Can you solve it without using extra space? 这个求单链表中的环的起始点是之前那个判断单链表中是否有环的延伸,可参见我之前的一篇文章 (http://www.cnblogs.com/grandyang/p/4137187.html). 还是要设…
Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 这道题是快慢指针的经典应用.只需要设两个指针,一个每次走一步的慢指针和一个每次走两步的快指针,如果链表里有环的话,两个指针最终肯定会相遇.实在是太巧妙了,要是我肯定想不出来.代码如下: C++ 解法: class Solution { public: bool hasCycle…
Design your implementation of the linked list. You can choose to use the singly linked list or the doubly linked list. A node in a singly linked list should have two attributes: val and next. val is the value of the current node, and next is a pointe…
这道题是LeetCode里的第707到题.这是在学习链表时碰见的. 题目要求: 设计链表的实现.您可以选择使用单链表或双链表.单链表中的节点应该具有两个属性:val 和 next.val 是当前节点的值,next 是指向下一个节点的指针/引用.如果要使用双向链表,则还需要一个属性 prev 以指示链表中的上一个节点.假设链表中的所有节点都是 0-index 的. 在链表类中实现这些功能: get(index):获取链表中第 index 个节点的值.如果索引无效,则返回-1. addAtHead(…
Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without using extra space? 给定一个链表,判断是否有环存在.Follow up: 不使用额外空间. 解法:双指针,一个慢指针每次走1步,一个快指针每次走2步的,如果有环的话,两个指针肯定会相遇. Java: public class Solution { public boolean hasCycle(Li…
Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 反向链表,分别用递归和迭代方式实现. 递归Iteration: 新建一个node(value=任意值, next = None), 用一个变量 next 记录head.next,head.next指向新node.next,新 node.next…
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Given linked list -- head = [4,5,1,9], which looks like following: 4 -> 5 -> 1 -> 9 Example 1: Input: head = [4,5,1,9], node = 5 Output:…