Type '' cannot conform to protocol '' because it has requirements that cannot be satisfied

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Type '' cannot conform to protocol '' because it has requirements that cannot be satisfied

我有一个Objective-C协议,我试图在Swift类中实现.例如: @class AnObjcClass; @protocol ObjcProtocol <NSObject> - (void)somethingWithAnArgument:(AnObjcClass *)arg; @end 当我尝试在这样的Swift类中符合它时: @objc class SwiftClass: NSObject, ObjcProtocol { // ... } 我得到以下可怕的编译器错误: Type ''…

type 'simple Class' does not conform to protocol 'Example Protocol'错误

在看swift教程中"接口和扩展"这小部分. 在编写时提示"type 'simple Class' does not conform to protocol 'Example Protocol'"的错误.原因是simpleClass没有全然实现protocol中定义的方法. 检查了下代码,原来是自己把方法名给写错了. mutating 仅仅针对 struct 和 enum .…

'String' does not conform to protocol 'CollectionType' Error in Swift 2.0

如下是报错需要修改的源码: // if count(currentPassword) < 6 || count(newPassword) < 6 || count(confirmPassword) < 6 { // var failAlertView = UIAlertView(title: Localized.ACCOUNT_HINT_PASSWORD , message: nil, delegate: self, cancelButtonTitle: Localized.DIALOG…

cannot conform to protocol 的一点事

学习UITableView过程中,回想视频打一遍代码,发现卡在了第一步.一直显示无法继承协议,而且还多了一个错误:definition conflicts with previous value.百度上也找不到什么原因,仔细一想才发现方法写错地方,看来很多错误还是出现在自己身上.要细心才行.以下是错误的示范: class ViewController: UIViewController, UITableViewDelegate ,UITableViewDataSource{ @IBOut…

Swift 给UITableView 写extension 时报错 does not conform to protocol 'UITableViewDataSource'

那是因为你没有实现数据源和代理方法实现下就好了 func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int { } func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell { return UITableViewCell() }…

Breaking Down Type Erasure in Swift

Type Erasure Pattern We can use the type erasure pattern to combine both generic type parameters and associated types to satisfy both the compiler and our flexibility goals. We will need to create three discrete types in order to satisfy these constr…