hdu1071

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hdu1071（抛物线弓形面积阿基米德算法）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1071 题意:给出抛物线的顶点和它与一直线的两交点,求他们围成的面积: 思路: 可以直接求出他们的方程式,再积分,这个方法就不说了: 偶然看见另一个解法,觉得蛮有意思的,就记一下好了.. 抛物线与直线为成的面积等于直线的平行线与抛物线的切点和该直线与抛物线两交点组成的三角形面积 s*4/3:(抛物线弓形面积公式等于:以割线为底,以平行于底的切线的切点为顶点的内接三角形的4/3,即:抛物线弓形面积=S+…

HDU1071 The area 【积分】

The area Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7476 Accepted Submission(s): 5222 Problem Description Ignatius bought a land last week, but he didn't know the area of the land becau…

The area （hdu1071）积分求面积

The area Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7066 Accepted Submission(s): 4959 Problem Description Ignatius bought a land last week, but he didn't know the area of the land because the…

hdu1071(定积分求面积)

太弱了,写了一下午,高中基础太差的孩子伤不起... 记住抛物线是关于x轴对称的. 而且抛物线的方程可以是: y=k(x-h)+c //其中(h,c)为顶点坐标 The area Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6080 Accepted Submission(s): 4247 Problem Description…

#include <iostream> #include <stdio.h> using namespace std; int main() { int t; double x1,y1,x2,y2,x3,y3,a,k,s; cin>>t; while(t--) { cin>>x1>>y1>>x2>>y2>>x3>>y3; a=(y2-y1)/((x2-x1)*(x2-x1)); k=(y2-y3)/…

HDU1071 The area

Ignatius bought a land last week, but he didn't know the area of the land because the land is enclosed by a parabola and a straight line. The picture below shows the area. Now given all the intersectant points shows in the picture, can you tell Ignat…

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