leetcode 83】的更多相关文章

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 这道题让我们移除给定有序链表的重复项,那么可以遍历这个链表,每个结点和其后面的结点比较,如果结点值相…
83. Remove Duplicates from Sorted List Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 这道题比较简单,去除链表中重复的数. 代码如…
https://leetcode.com/problems/remove-duplicates-from-sorted-list/ 题目: Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->…
Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 题目标签:Linked List 题目给了我们一个 list,让我们去除中间的重复项. 设一个 cursor = head…
83. 删除排序链表中的重复元素 给定一个排序链表,删除所有重复的元素,使得每个元素只出现一次. 示例 1: 输入: 1->1->2 输出: 1->2 示例 2: 输入: 1->1->2->3->3 输出: 1->2->3 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { v…
83. 删除排序链表中的重复元素 问题描述 给定一个排序链表,删除所有重复的元素,使得每个元素只出现一次. 示例 1: 输入: 1->1->2 输出: 1->2 示例 2: 输入: 1->1->2->3->3 输出: 1->2->3 代码(快慢指针法) * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int…
就是将链表中的重复元素去除 我的方法很简单就是如果链表的前后元素相同的话,将后一个元素删除 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* deleteDuplicates(ListNode* he…
题目描述: Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 代码如下: 代码一,正常解法: /** * Definition for singly-linked list…
描述 Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2Output: 1->2Example 2: Input: 1->1->2->3->3Output: 1->2->3 有序链表去重. 解析 移除给定有序链表的重复项,那么我们可以遍历这个链表,每个结点和其后面的结点比较…
Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 题意: 有序链表去重 思路: 代码: class Solution { public ListNod…