643. 子数组最大平均数 I 643. Maximum Average Subarray I 题目描述 给定 n 个整数,找出平均数最大且长度为 k 的连续子数组,并输出该最大平均数. LeetCode643. Maximum Average Subarray I 示例 1: 输入: [1,12,-5,-6,50,3], k = 4 输出: 12.75 解释: 最大平均数 (12-5-6+50)/4 = 51/4 = 12.75 注意: 1 <= k <= n <= 30,000. 所…

作者: 负雪明烛 id: fuxuemingzhu 公众号:每日算法题 目录 题目描述 题目大意 解题方法 方法一:preSum 方法二:滑动窗口 刷题心得 日期 题目地址:https://leetcode.com/problems/maximum-average-subarray-i/description/ 题目描述 Given an array consisting of n integers, find the contiguous subarray of given length k…

Given an array consisting of n integers, find the contiguous subarray of given length k that has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximu…

643. 子数组最大平均数 I 给定 n 个整数,找出平均数最大且长度为 k 的连续子数组,并输出该最大平均数. 示例 1: 输入: [1,12,-5,-6,50,3], k = 4 输出: 12.75 解释: 最大平均数 (12-5-6+50)/4 = 51/4 = 12.75 注意: 1 <= k <= n <= 30,000. 所给数据范围 [-10,000,10,000]. class Solution { public double findMaxAverage(int[] n…

子数组最大平均数I 给定 n 个整数,找出平均数最大且长度为 k 的连续子数组,并输出该最大平均数. 示例 1: 输入: [1,12,-5,-6,50,3], k = 4 输出: 12.75 解释: 最大平均数 (12-5-6+50)/4 = 51/4 = 12.75 注意: 1 <= k <= n <= 30,000. 所给数据范围 [-10,000,10,000]. 思路 本题拿到手的时候,第一个思路就是对每一个元素都去求其长度为k的连续子数组的平均数,最后比较返回最大平均数,这样的…

题目 给定 n 个整数,找出平均数最大且长度为 k 的连续子数组,并输出该最大平均数. 示例: 输入:[1,12,-5,-6,50,3], k = 4 输出:12.75 解释:最大平均数 (12-5-6+50)/4 = 51/4 = 12.75 提示: 1 <= k <= n <= 30,000. 所给数据范围 [-10,000,10,000]. 来源:力扣(LeetCode) 链接:子数组最大平均数I 著作权归领扣网络所有.商业转载请联系官方授权,非商业转载请注明出处. 分析 力扣在编…

Given an array consisting of n integers, find the contiguous subarray whose length is greater than or equal to k that has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output:…

Given an array consisting of n integers, find the contiguous subarray whose length is greater than or equal to k that has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output:…

problem 643. Maximum Average Subarray I 题意:一定长度的子数组的最大平均值. solution1:计算子数组之后的常用方法是建立累加数组,然后再计算任意一定长度的子数组之和,迭代更新得到最大值. 注意:1)累加数组:2)数值类型: class Solution { public: double findMaxAverage(vector<int>& nums, int k) { vector<); //vector<int> s…

［抄题］: Given an array consisting of n integers, find the contiguous subarray of given length k that has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation:…