leetcode - 34. Search for a Range - Medium descrition Given an array of integers sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the ta…

原题目:Search for a Range, 现在题目改为: 34. Find First and Last Position of Element in Sorted Array Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

Given an array of integers sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For e…

https://leetcode.com/problems/search-for-a-range/ Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the…

题目链接: https://leetcode.com/problems/search-for-a-range/?tab=Description   Problem: 在已知递减排序的数组中,查找到给定数字的起止下标   采用两遍扫描: 第一遍扫描得到给定数字的起始下标,(从下标i==0开始到nums.lenght-1) 第二遍扫描从第一遍扫描得到的下标开始进行扫描    参考代码: package leetcode_50; /*** * * @author pengfei_zheng * 数组中…

1 题目: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given […

题目描述: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 34: Search for a Rangehttps://oj.leetcode.com/problems/search-for-a-range/ Given a sorted array of integers, find the starting and ending position of a given target value.Your algorithm's r…

索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 035. Search for a Range (Medium) 链接: 题目:https://leetcode.com/problems/search-for-a-range/ 代码(github):https://github.com/illuz/leetcode 题意: 在有序数组中找到一个数的范围.(由于数…

一天一道LeetCode系列 (一)题目 Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

题目要求:Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. F…

1. 原题链接 https://leetcode.com/problems/search-for-a-range/description/ 2. 题目要求 给定一个按升序排列的整型数组nums[ ]和目标值target(int类型),如果数组中存在目标值,返回目标值在数组中的起始位置和结束位置,[start, end].不存在返回 [-1, -1]. 3. 解题思路 思路一:暴力解决,遍历数组进行匹配,时间复杂度O( n ) 4. 代码实现 package com.huiAlex; public…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5, 7,…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5, 7,…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5, 7,…

题目: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5,…

Link: https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the targe…

题目: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5,…

题目描述: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given [5, 7,…

题目意思:递增数组,找到目标数的范围,找不到则返回[-1,-1] 思路:折半查找 class Solution { public: vector<int> searchRange(vector<int>& nums, int target) { ,end=nums.size()-; vector<int> ans; while(start<=end){ ; if(nums[temp]>target){ end=temp-; } else if(num…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given [5, 7,…

题目: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5,…

LintCode 61. Search for a Range (Medium) LeetCode 34. Search for a Range (Medium) class Solution { private: int findBound(vector<int> &A, int target, bool findLowerBound) { int L = 0, R = A.size() - 1; while (L <= R) { int M = L + (R - L) / 2…

[一天一道LeetCode]汇总目录 这篇博客主要收藏了博主所做题目的索引目录,帮助各位读者更加快捷的跳转到对应题目 目录按照难易程度:easy,medium,hard来划分,读者可以按照难易程度进行练习 (一)easy [一天一道LeetCode] #1 Two Sum [一天一道LeetCode]#6 ZigZag Conversion [一天一道LeetCode]#7. Reverse Integer [一天一道LeetCode]#8. String to Integer (atoi) […

最近做的题记录下. 258. Add Digits Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. int addDigi…