890. Find and Replace Pattern - LeetCode】的更多相关文章

Question 890. Find and Replace Pattern Solution 题目大意:从字符串数组中找到类型匹配的如xyy,xxx 思路: 举例:words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb" abb -> 011 abc -> 012 deq -> 0…
You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…
You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典+set 单字典 日期 题目地址:https://leetcode.com/problems/find-and-replace-pattern/description/ 题目描述 You have a list of words and a pattern, and you want to know which words in words ma…
把pattern映射到数字,也就是把pattern标准化. 比如abb和cdd如果都能标准化为011,那么就是同构的. class Solution: def findAndReplacePattern(self, words: List[str], pattern: str) -> List[str]: p = self.get_pattern(pattern) ans = [] for w in words: if self.get_pattern(w) == p: ans.append(w…
[抄题]: You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get…
You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…
Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. You may assume the given string consists of lowercase English letters only and its length will not exceed 100…
Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat cat d…
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