链接: http://acm.hdu.edu.cn/showproblem.php?pid=2199 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 13475    Accepted Submission(s): 6010 Problem Description Now,given the equation 8*x^4 + 7*x^3…
Now,given the equation 8x^4 + 7x^3 + 2x^2 + 3x + 6 == Y,can you find its solution between 0 and 100; Now please try your lucky. Input The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines fol…
http://acm.hdu.edu.cn/howproblem.php?pid=2199 Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 13468    Accepted Submission(s): 6006 Problem Description Now,given the…
HDU 2199 Can you solve this equation?     Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100; Now please try your lucky. InputThe first line of the input contains an integer T(1<=T<=100) which mea…
传送门: http://acm.hdu.edu.cn/showproblem.php?pid=2199 Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 25039    Accepted Submission(s): 10776 Problem Description Now,gi…
Can you solve this equation? Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Now,given the equation *x^ + *x^ + *x^ + *x + == Y,can you find its solution between and ; No…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7156    Accepted Submission(s): 3318 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7493    Accepted Submission(s): 3484 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 6023    Accepted Submission(s): 2846 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 27728    Accepted Submission(s): 11717 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 ==…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 22742    Accepted Submission(s): 9865 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 ==…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6763    Accepted Submission(s): 3154 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5999    Accepted Submission(s): 2828 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,…
解题思路:给出一个方程 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,求方程的解. 首先判断方程是否有解,因为该函数在实数范围内是连续的,所以只需使y的值满足f(0)<=y<=f(100),就一定能找到该方程的解,否则就无解. 然后是求解过程, 假设一个区间[a,b],mid=(a+b)/2,如果f(a)*f(b)<0,那么函数f(x)在区间[a,b]至少存在一个零点,如果f(a)<0,说明0点在其右侧,那么将a的值更新为当前mid的值,如果f(a)&g…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12766    Accepted Submission(s): 5696 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y…
链接:http://acm.hdu.edu.cn/showproblem.php?pid=2199 Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8595    Accepted Submission(s): 3957 Problem Description Now,given…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5667    Accepted Submission(s): 2681http://acm.hdu.edu.cn/showproblem.php?pid=2199 Problem Description Now,given the…
Can you solve this equation? Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 61   Accepted Submission(s) : 37 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can y…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1182 Accepted Submission(s): 558   Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can…
Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 25633    Accepted Submission(s): 11018 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 ==…
Solve a given equation and return the value of x in the form of string "x=#value". The equation contains only '+', '-' operation, the variable x and its coefficient. If there is no solution for the equation, return "No solution". If th…
D - Can you solve this equation? Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;Now please try your lucky. InputThe first line of the input contains an integer T(1<=T<=100) which means the num…
[LeetCode]640. Solve the Equation 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/solve-the-equation/description/ 题目描述: Solve a given equation and return the value of x in the…
明天来一发 hdu 4501  算是这题的简化版吧…
Now,given the equation 8x^4 + 7x^3 + 2x^2 + 3x + 6 == Y,can you find its solution between 0 and 100; Now please try your lucky. Input The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines fol…
#include<stdio.h> #include<math.h> double f(double x) { return 8*x*x*x*x+7*x*x*x+2*x*x+3*x+6; } int main(void) { int t; double y,x1,x2,x3,y1,y2,y3; scanf("%d",&t); while(t--) { scanf("%lf",&y); x1=0; x2=100; y1=f(x1…
题意 给Y值,找到多项式 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y 在0到100之间的解. 思路 从0到100,多项式是单调的,故用二分法求解. 代码 double calc(double x){ return 8*x*x*x*x+7*x*x*x+2*x*x+3*x+6; } int main(){ int T; cin>>T; while(T--){ double Y; cin>>Y; double L,R; L = 0.0, R= 100.0;…
Problem Description Now,given the equation 8x^4 + 7x^3 + 2x^2 + 3x + 6 == Y,can you find its solution between 0 and 100; Now please try your lucky. Input The first line of the input contains an integer T(1<=T<=100) which means the number of test cas…
本题是一道二分的题,核心就是mi的大小,即精度的取值.因为原函数是一个单调递增的函数,所以可以确定y的取值范围,并且在范围内的每一个y的值,一定至少存在一个x与其对应.刚开始我将取二分这个环节用一个函数来表示的,但是返回值始终是一个随机值,实在是搞不懂,无奈之下只能将那个步骤直接写在主函数内... #include"iostream" #include"stdio.h" #include"algorithm" #include"stri…
题意:给出一个数让你求出等于这个数的x 策略:如题. 由于整个式子是单调递增的.所以能够用二分. 要注意到精度. 代码: #include <stdio.h> #include <string.h> #include <math.h> #define eps 1e-10 #define f(x) 8*pow(x, 4) + 7*pow(x, 3) + 2*pow(x, 2) + 3*x int main() { int t; double n; scanf("…