POJ1338 2545 2591 2247都是一个类型的题目,所以放到一起来总结 POJ1338:Ugly Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21708   Accepted: 9708 Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence  1, 2, 3, 4,…

POJ1338 2545 2591 2247都是一个类型的题目,所以放到一起来总结 POJ1338:Ugly Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21708   Accepted: 9708 Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence  1, 2, 3, 4,…

[POJ1338]Ugly Numbers 试题描述 Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, ... shows the first 10 ugly numbers. By convention, 1 is included. Given the integer n,write a program to find an…

DP 水题 Description A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, ... shows the first 20 humble numbers. Write a program to find and print…

打表大军是一股邪恶势力→_→ #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <cctype> #include <cmath> #include <numeric> #include <algorithm> #include <limits.h> #include <ve…

                                                                             Ugly Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 19952   Accepted: 8856 Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5.…

问题描述 判断一个由 a-z 这 26 个字符组成的字符串中哪个字符出现的次数最多 输入:第 1 行是测试数据的组数 n,每组测试数据占 1 行,是一个由 a-z 这 26 个字符组 成的字符串,每组测试数据之间有一个空行,每行数据不超过 1000 个字符且非空 输出:n 行,每行输出对应一个输入.一行输出包括出现次数最多的字符和该字符出现的 次数,中间是一个空格. 如果有多个字符出现的次数相同且最多,那么输出 ascii 码最小的那一个字符. 输入样例 2 abbccc adfadffasdf…

题意:一个数的质因子能是2, 3, 5, 那么这个数是丑数. 思路: 打表或者递推. 打表: 若该数为丑数,那么一定能被2 或者3, 或者5 整除, 除完之后则为1. #include <iostream> #include <fstream> using namespace std; ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,…

我记得这道题以前写过,而且是写出来了.DP吧. 然后现在想了好久...没想出来.... 然后考虑一下递推..mdzz-直接就是让之前的这个每次乘以2,3,5就好了嘛,然后每轮取最小. //#include <bits/stdc++.h> #include<iostream> #include<cstdio> #include<math.h> #include<string.h> #include<algorithm> using na…

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