Tower of Hanoi Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 1895   Accepted: 646 Description The Tower of Hanoi is a puzzle consisting of three pegs and a number of disks of different sizes which can slide onto any peg. The puzzle st…

Tower of Hanoi Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 1853   Accepted: 635 Description The Tower of Hanoi is a puzzle consisting of three pegs and a number of disks of different sizes which can slide onto any peg. The puzzle st…

Strange Towers of Hanoi 大体意思是要求\(n\)盘4的的hanoi tower问题. 总所周知,\(n\)盘3塔有递推公式\(d[i]=dp[i-1]*2+1\) 令\(f[i]\)为4塔转移步骤. \(f[i]=min(f[i],f[k]*2+d[i-k])\) 即先以4塔以上面的\(k\),再以3塔移\(i-k\),最后以4塔移动回去. 可以推广到\(n\)盘\(m\)塔 2018.5.26…

Strange Towers of Hanoi Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 3784 Accepted: 2376 Description Background  Charlie Darkbrown sits in another one of those boring Computer Science lessons: At the moment the teacher just explains the…

[题目链接] http://poj.org/problem?id=1958 [算法] 先考虑三个塔的情况,g[i]表示在三塔情况下的移动步数,则g[i] = g[i-1] * 2 + 1 再考虑四个塔的情况,f[i]表示在四塔情况下的移动步数,则f[i] = min{2*f[j]+g[i-j]} [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #i…

Hanoi Towers Time Limit : 10000/5000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 0 Accepted Submission(s) : 0 Special Judge Problem Description The “Hanoi Towers” puzzle consists of three pegs (that we will name A,…

Towers of Hanoi Time Limit: 3000MS   Memory Limit: 16000K Total Submissions: 2213   Accepted: 986 Case Time Limit: 1000MS Description Surely you have already come across the Towers of Hanoi problem: Wooden disks of different sizes are stacked on thre…

题意:就是让你求出4个塔的汉诺塔的最小移动步数,(1 <= n <= 12) 那么我们知道3个塔的汉诺塔问题的解为:d[n] = 2*d[n-1] + 1 ,可以解释为把n-1个圆盘移动到一个临时柱子上,然后将1个最大圆盘移动到目标的主子,最后再将n-1个圆盘移动到目标柱子. 为什么是n-1和1的组合呢,因为当你将n-i个圆盘移动到一个临时柱子上的时候,你会发现只靠两个柱子最多能移动1个圆盘.所以这个i=1 如果推到到4个柱子的汉诺塔,f[n] = min(f[n],2*f[n-i]+d[i]…

Log 2016-3-21 网上找的POJ分类,来源已经不清楚了.百度能百度到一大把.贴一份在博客上,鞭策自己刷题,不能偷懒!! 初期: 一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. (4)递推. (5)构造法.(poj3295) (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996) 二.图算法: (1)图的深度优先遍历和广度优先遍历. (2)最短路…

初期:一.基本算法:     (1)枚举. (poj1753,poj2965)     (2)贪心(poj1328,poj2109,poj2586)     (3)递归和分治法.     (4)递推.     (5)构造法.(poj3295)     (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996)二.图算法:     (1)图的深度优先遍历和广度优先遍历.     (2)最短路径算法(dijkstra,bellman-ford,floyd,hea…