给定一个二叉搜索树,同时给定最小边界L 和最大边界 R.通过修剪二叉搜索树,使得所有节点的值在[L, R]中 (R>=L) .你可能需要改变树的根节点,所以结果应当返回修剪好的二叉搜索树的新的根节点. 错误的答案: class Solution { public: TreeNode* trimBST(TreeNode* root, int L, int R) { if(root == NULL) return NULL; if(root ->val < L) { root = root…

669. 修剪二叉搜索树 669. Trim a Binary Search Tree 题目描述 LeetCode LeetCode669. Trim a Binary Search Tree简单 Java 实现 TreeNode Class public class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } } class Solution { public TreeNode…

problem 669. Trim a Binary Search Tree 参考 1. Leetcode_easy_669. Trim a Binary Search Tree; 完…

Week2 - 669. Trim a Binary Search Tree & 617. Merge Two Binary Trees 669.Trim a Binary Search Tree Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You migh…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

题目: Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed bi…

  Given a binary search tree and the lowest and highest boundaries as `L`and `R`, trim the tree so that all its elements lies in `[L, R]` (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed…

题目要求 Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed b…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

［抄题］: Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

[题目] Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with…

题目: Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed bi…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/problems/trim-a-binary-search-tree/description/ 题目描述 Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree…

这是悦乐书的第284次更新,第301篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第152题(顺位题号是669).给定二叉搜索树以及L和R的最低和最高边界,修剪树以使其所有元素位于[L,R](R> = L).可能需要更改树的根,因此结果应返回修剪后的二叉搜索树的新根.例如: 输入:L = 1 R = 2 1 / \ 0 2 输出: 1 \ 2 输入:L = 1 R = 3 3 / \ 0 4 \ 2 / 1 输出: 3 / 2 / 1 本次解题使用的开发工具是ecl…

题目就是给出一棵二叉搜索树,已知根节点为0,并且给出一个序列要插入到这课二叉树中,求这棵二叉树层次遍历后的序列. 用结构体建立节点,val表示该节点存储的值,left指向左孩子,right指向右孩子.中序遍历的顺序正好是序列从小到大的顺序,因此中序遍历的时候顺便赋值就可以了,最后层次遍历输出. 思路一:中序遍历的时候赋值 #include <iostream> #include <cstdio> #include <algorithm> #include <str…

根据BST的特点,如果小于L就判断右子树,如果大于R就判断左子树 递归地建立树 public TreeNode trimBST(TreeNode root, int L, int R) { if (root==null) return null; if (root.val<L) return trimBST(root.right,L,R); if (root.val>R) return trimBST(root.left,L,R); TreeNode res = new TreeNode(ro…

Source: PAT A1043 Is It a Binary Search Tree (25 分) Description: A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key.…

Source: PAT A1064 Complete Binary Search Tree (30 分) Description: A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key…

二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现.由于篇幅有限,此处仅作一般介绍(如果想要完全了解二叉树以及其衍生出的各种算法,恐怕要写8~10篇). 1)二叉树(Binary Tree) 顾名思义,就是一个节点分出两个节点,称其为左右子节点:每个子节点又可以分出两个子节点,这样递归分叉,其形状很像一颗倒着的树.二叉树限制了每个节点最多有两个子节…

4.7 Design an algorithm and write code to find the first common ancestor of two nodes in a binary tree. Avoid storing additional nodes in a data structure. NOTE: This is not necessarily a binary search tree. LeetCode上的原题,请参见我之前的博客Lowest Common Ancest…

Return the root node of a binary search tree that matches the given preorder traversal. (Recall that a binary search tree is a binary tree where for every node, any descendant of node.left has a value < node.val, and any descendant of node.right has…

1043 Is It a Binary Search Tree(25 分) A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a nod…

既上篇关于二叉搜索树的文章后,这篇文章介绍一种针对二叉树的新的中序遍历方式,它的特点是不需要递归或者使用栈,而是纯粹使用循环的方式,完成中序遍历. 线索二叉树介绍 首先我们引入“线索二叉树”的概念: "A binary tree is threaded by making all right child pointers that would normally be null point to the inorder successor of the node, and all left chi…

树的题目,往往可以用到三种遍历.以及递归,因为其结构上天然地可以往深处递归,且判断条件也往往不复杂(左右子树都是空的). LeetCode 98题讲的是,判断一棵树是不是二叉搜索树. 题目中给的是标准定义:即一个二叉搜索树(binary search tree,简称BST)的每个节点都满足:1.其左侧的整个子树的值都比它小:2.其右侧的整个子树的值都比他大:3.它的左右子树依旧保持二叉搜索树的结构. 第0步 一开始理解错了条件,容易理解成,每个节点只需要比它的左子树大,比它的右子树小,于是得到了…

1064 Complete Binary Search Tree (30)(30 分) A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of…