Question 559. Maximum Depth of N-ary Tree Solution 题目大意:N叉树求最大深度 思路:用递归做,树的深度 = 1 + 子树最大深度 Java实现: /* // Definition for a Node. class Node { public int val; public List<Node> children; public Node() {} public Node(int _val,List<Node> _children…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

题目要求 Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题目分析及思路 题目给出一个N叉树,要求得到它的最大深度.该最大深度为根结点到最远叶结点的结点数.可以使用递归,遍历孩子结点. python代码​ """…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. /* // Definiti…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS BFS 日期 题目地址:https://leetcode.com/problems/maximum-depth-of-n-ary-tree/description/ 题目描述 Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

原题链接 思路: 简单bfs class Solution { public: int maxDepth(Node *root) { int depth = 0; if (root == NULL) return 0; queue<Node *> q; q.push(root); while (q.size() > 0) { depth++; int len = q.size(); for (int i = 0; i < len; i++) { vector<Node *&g…

https://leetcode.com/problems/maximum-depth-of-n-ary-tree/description/ 非常简单的题目,连edge case 都没有.思路就是:最大深度 = 孩子的最大深度 + 1 /* // Definition for a Node. class Node { public: int val; vector<Node*> children; Node() {} Node(int _val, vector<Node*> _ch…