注意:getMin()时间复杂度为O(1) 最原始的方法: class MinStack(object): def __init__(self): """ initialize your data structure here. """ self.stack=[] def push(self, x): """ :type x: int :rtype: void """ # self.st…

No.154 FindMin 寻找旋转排序数组中的最小值 II 题目 假设按照升序排序的数组在预先未知的某个点上进行了旋转. ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] ). 请找出其中最小的元素. 注意数组中可能存在重复的元素. 示例 输入: [1,3,5] 输出: 1 输入: [2,2,2,0,1] 输出: 0 说明 这道题是 No.153 寻找旋转排序数组中的最小值 的延伸题目. 允许重复会影响算法的时间复杂度吗?会如何影响,为什么? 思路 代…

下面题目是LeetCode算法155题: https://leetcode.com/problems/min-stack/ 题目1:最小函数min()栈 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. package com.good.good.study.stack; import java.uti…

155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } void push(int x) { if(s1.empty() && s2.empty()){ s1.push(x); s2.push(x); } else{ if(x < s2.top()){ s1.push(x); s2.push(x); } else{ s1.push(x); s2…

LeetCode 155:最小栈 Min Stack 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. pu…

155. Min Stack class MinStack { int min = Integer.MAX_VALUE; Stack<Integer> stack = new Stack<Integer>(); /** initialize your data structure here. */ public MinStack() { } public void push(int x) { if(x <= min){ stack.push(min); min = x; }…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

155. 最小栈 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) – 将元素 x 推入栈中. pop() – 删除栈顶的元素. top() – 获取栈顶元素. getMin() – 检索栈中的最小元素. 示例: MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> 返回…

155. 最小栈 知识点:栈:单调 题目描述 设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. 示例 输入: ["MinStack","push","push","push","getMin","po…

李洪强iOS经典面试题155 - const,static,extern详解(面试必备) 一.const与宏的区别(面试题): const简介:之前常用的字符串常量,一般是抽成宏,但是苹果不推荐我们抽成宏,推荐我们使用const常量. 执行时刻:宏是预编译(编译之前处理),const是编译阶段. 编译检查:宏不做检查,不会报编译错误,只是替换,const会编译检查,会报编译错误. 宏的好处:宏能定义一些函数,方法. const不能. 宏的坏处:使用大量宏,容易造成编译时间久,每次都需要重新替换.…

题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the min…

#-*- coding: UTF-8 -*- class MinStack(object):    def __init__(self):        """        initialize your data structure here.        """        self.Stack=[]        self.minStack=[]            def push(self, x):        "&…

Implement a stack with min() function, which will return the smallest number in the stack. It should support push, pop and min operation all in O(1) cost. Example push(1) pop() // return 1 push(2) push(3) min() // return 2 push(1) min() // return 1 p…

https://leetcode.com/problems/min-stack/ #include <vector> #include <queue> #include <map> #include <iostream> using namespace std; class MinStack { public: vector<int> vec; priority_queue<int,vector<int>,greater<…

题意:设计一个能输出栈内最小值的栈 该题设计两个栈,一个栈是正常的栈s,而另一个是存最小值的栈sm 在push时要判断sm是否为空,如果为空或者非空但是栈顶元素大于等于插入值的 需要在sm中插入x 同样地在pop时,s的元素被删除了,那么sm中的也应该被删除. 通过这些操作维护sm能很巧妙在O(1)复杂度得到最小值. class MinStack { public: stack<int> sm; stack<int> s; void push(int x) { s.push(x);…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

[福吧资源网分享]课程是非常完整的,也是非常零基础的,适合任何学员,有需要的可以下载看看!课程目录:第1章 Adobe Photoshop CS6课时1 Adobe Photoshop CS6入门基础 52:24课时2 创建与编辑选区(上) 46:57课时3 创建与编辑选区(下) 48:59课时4 掌握图层与图层组(上) 48:01课时5 掌握图层与图层组(下) 57:35课时6 绘制位图图像(上) 47:46课时7 绘制位图图像(下) 46:37课时8 绘制矢量图形(上) 46:49课时9 绘…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.    pop() -- Removes the element on top of the stack.    top() -- Get the top element.    getMin() -- Retrieve the…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

1- 问题描述 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the m…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the min…

题目: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minim…

新概念英语(1-55)The Sawyer family When do the children do their homework? The Sawyers live at 87 King Street. In the morning, Mr. Sawyer goes to work and the children go to school. Their father takes them to school everyday. Mrs Sawyer stays at home every…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) – Push element x onto stack. pop() – Removes the el…

题目链接:https://leetcode-cn.com/problems/min-stack/description/ 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中.pop() -- 删除栈顶的元素.top() -- 获取栈顶元素.getMin() -- 检索栈中的最小元素. 题解: 以往,我们经常用 $min[i]$ 维护区间 $[1,i]$ 的最小值,在这里我们同样也可以这么做. AC代码(要想超过百分百的c…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.    pop() -- Removes the element on top of the stack.    top() -- Get the top element.    getMin() -- Retrieve the…

https://leetcode.com/problems/min-stack/#/solutions Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get…

tag: 栈(stack) 题目描述 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. 示例: MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.get…

设计包含 min 函数的栈(栈)定义栈的数据结构,要求添加一个 min 函数,能够得到栈的最小元素.要求函数 min.push 以及 pop 的时间复杂度都是 O(1). #include <algorithm> #include <iostream> #include <exception> #include <string> class illegalParameterValue { public: illegalParameterValue():err…