[leetcode] 392. Is Subsequence (Medium)】的更多相关文章

原题 判断子序列 /** * @param {string} s * @param {string} t * @return {boolean} */ var isSubsequence = function(s, t) { var sl = s.length; var tl = t.length; if (sl === 0) { return true; } if (tl < sl) { return false; } var sindex = 0; for (let i = 0; i <…
Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100). A subsequence of…
Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and sis a short string (<=100). A subsequence of a…
题目详情 给定字符串 s 和 t ,判断 s 是否为 t 的子序列. 你可以认为 s 和 t 中仅包含英文小写字母.字符串 t 可能会很长(长度 ~= 500,000),而 s 是个短字符串(长度 <=100). 字符串的一个子序列是原始字符串删除一些(也可以不删除)字符而不改变剩余字符相对位置形成的新字符串.(例如,"ace"是"abcde"的一个子序列,而"aec"不是). 示例 1: s = "abc", t =…
[LeetCode]392. Is Subsequence 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/is-subsequence/description/ 题目描述: Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters…
392. Is Subsequence 水题,先是判断长度,长度t比s小,返回false,然后从左到右扫描t,然后同时扫描s,如果相同,s的index就往后拉一个,如果s的index等于s长度,返回true,否则,返回false.…
leetcode - 48. Rotate Image - Medium descrition You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Note: You have to rotate the image in-place, which means you have to modify the input 2D matrix direct…
leetcode - 39. Combination Sum - Medium descrition Given a set of candidate numbers (C) (without duplicates) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from…
leetcode - 31. Next Permutation - Medium descrition Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible…
题意: 求最长增长的子序列的长度. 思路: 利用DP存取以i作为最大点的子序列长度. Runtime: 20 ms, faster than 35.21% of C++ online submissions for Longest Increasing Subsequence. class Solution { public: int lengthOfLIS(vector<int> &nums) { ) ; vector<); dp[] = ; ; ; i < nums.s…