LeetCode--single-number系列 Question 1 Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Soluti…

题目:singleNumber Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 给一个数组里面除了唯一的一个数只出现一次,其他每个数都…

/** * Source : https://oj.leetcode.com/problems/single-number/ * * * Given an array of integers, every element appears twice except for one. Find that single one. * * Note: * Your algorithm should have a linear runtime complexity. Could you implement…

SingleNumber I: 题目链接:https://leetcode-cn.com/problems/single-number/ 题意: 给定一个非空整数数组,除了某个元素只出现一次以外,其余每个元素均出现两次.找出那个只出现了一次的元素. 说明: 你的算法应该具有线性时间复杂度. 你可以不使用额外空间来实现吗? 示例 1: 输入: [2,2,1] 输出: 1 示例 2: 输入: [4,1,2,1,2] 输出: 4 分析: 利用异或(xor)运算,两个相同的数异或为0 代码如下: cla…

Leetccode 136 SingleNumber I Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 1.自己想到了先排序,再遍历数…

Given an array of integers, every element appears three times except for one. Find that single one. solution: def singleNumber(self,A): A.sort() for i in range(0,len(A)): if i%3=0 && A[i]!=A[i+1] && A[i]!=A[i+2kjk]: return A[i-1] if __name…

Given an array of integers, every element appears twice except for one. Find that single one. solution: class solution: def singleNumber(self,A): A.sort() for i in range(1,len(A)): if i%2=1 && A[i]!=A[i-1]: return A[i-1] if __name__ == '__main__':…

Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? C++ class Solution { public: int singleNumb…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…

Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 这道题是之前那道 Single Number 单独的数字的延伸,那道题的解法…