题目链接: Inversion Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1087    Accepted Submission(s): 323 Problem Description You have a sequence {a1,a2,...,an} and you can delete a contiguous subsequ…

Problem Description You have a sequence {a1,a2,...,an} and you can delete a contiguous subsequence of length m. So what is the minimum number of inversions after the deletion.   Input There are multiple test cases. The first line of input contains an…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1394 Minimum Inversion Number                        Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)                                            Total Submission(s): 10…

控制反转和依赖注入 控制反转和依赖注入是两个密不可分的方法用来分离你应用程序中的依赖性.控制反转Inversion of Control (IoC) 意味着一个对象不会新创建一个对象并依赖着它来完成工作.相反,它们从外部获取它们想要的对象.依赖注入Dependency Injection (DI) 意味着在没有对象的干预下,一般通过能传入构造参数和一系列属性的框架组件完成.马丁虎老二(Martin Fowler)写过一篇关于依赖注入和控制反转的牛B文章,我就不要再抄到这儿了,你可以在这儿找到.N…

Minimum Inversion Number [题目链接]Minimum Inversion Number [题目类型]最小逆序数 线段树 &题意: 求一个数列经过n次变换得到的数列其中的最小逆序数 &题解: 先说一下逆序数的概念: 在一个排列中,如果一对数的前后位置与大小顺序相反,即前面的数大于后面的数,那末它们就称为一个逆序. 一个排列中逆序的总数就称为这个排列的逆序数.逆序数为偶数的排列称为偶排列:逆序数为奇数的排列称为奇排列. 如2431中,21,43,41,31是逆序,逆序数…

很多软件工程师都多少在处理 "Bad Design"时有一些痛苦的经历.如果发现这些 "Bad Design" 的始作俑者就是我们自己时,那感觉就更糟糕了.那么,到底是什么让我做出一个能称为 "Bad Design" 的设计呢? 绝大多数软件工程师不会在设计之初就打算设计一个 "Bad Design".许多软件也在不断地演化中逐渐地降级到了一个点,而从这个点开始,有人开始说这个设计已经腐烂到一定程度了.为什么会发生这些事情呢?…

题目链接: 传送门 Minimum Inversion Number Time Limit: 1000MS     Memory Limit: 32768 K Description The inversion number of a given number sequence a1, a2, ..., an is the number of pairs (ai, aj) that satisfy i < j and ai > aj. For a given sequence of numbe…

Description For sequence i1, i2, i3, … , iN, we set aj to be the number of members in the sequence which are prior to j and greater to j at the same time. The sequence a1, a2, a3, … , aN is referred to as the inversion sequence of the original sequen…

Inversion Sequence Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%lld & %llu Description For sequence i1, i2, i3, … , iN, we set aj to be the number of members in the sequence which are prior to j and greater to j at the same time.…

C - Minimum Inversion Number Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description The inversion number of a given number sequence a1, a2, ..., an is the number of pairs (ai, aj) that satisfy i < j and ai > aj.…