Rikka with Competition 给出一个大小为n的集合\(\{a_i\}\),每次从集合中随机挑出一对数\(a_i,a_j\),如果\(|a_i-a_j|>K\),那么从集合中删掉较小的那个数字,否则随机删掉一个数字,显然会有一个数字保留到最后,现在询问能够有可能保留到最后一个数字的数字个数,\(n\leq 10^5\). 解 序列无序,不妨排个序构成一个序列,显然序列最后一个元素必然有机会留到最后,此时考虑倒数第二个元素,如果它和最后一个元素的差的绝对值不超过K那么也有机会保留到…

Problem Description As we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them: A wrestling match will be held tomorrow. n players will take part in it. The ith player…

2017-09-22 22:01:19 writer:pprp As we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them: A wrestling match will be held tomorrow. nn players will take part in it. T…

题意:给定$n$个数,代表$n$个选手的能量高低,现在再给一个$k$,任意在$n$个选手中挑取两个选手比赛,如果$|a_i−a_j|>K$,那么能量高的选手获胜,另一个将被淘汰,否则两个人都有机会获胜,现在要你求有多少人有获胜的可能 分析:只需要排一下序,判断$a[i]-a[i+1]>m$的个数即可.因为排序后,相邻的如果都无法满足这个条件,那他一定被淘汰:反之,他就*有可能*获胜. #include <bits/stdc++.h> using namespace std; typ…

[Link]: [Description] [Solution] 把所有人的能力从大到小排; 能力最大的肯定可能拿冠军; 然后一个一个地往后扫描; 一旦出现a[i-1]-a[i]>k; 则说明从这以后的人,都不可能再和有实力拿冠军的人竞争了 无论怎么安排都赢不了那部分可能拿冠军的人. [NumberOf WA] [Reviw] [Code] #include <bits/stdc++.h> using namespace std; #define lson l,m,rt<<1…

签到题目,排序然后按序清理掉一定会输的结果就可以. ac代码: #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ]; int main() { int t; cin>>t; while(t--) { int n,k; ; scanf("%d %d",&n,&k);…

Rikka with Competition Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 445    Accepted Submission(s): 366 Problem Description As we know, Rikka is poor at math. Yuta is worrying about this situ…

Rikka with Competition Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 772    Accepted Submission(s): 588 Problem Description As we know, Rikka is poor at math. Yuta is worrying about this situa…

HDU6095——Rikka with Competition 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6095 题目意思:抱歉虽然是签到题,现场真的没做出来,因为题目没看懂,题目说明现在给出n个选手的能力值,现在举办n-1场比赛,如果每场比赛中选出的两名选手之间能力的差大于k,则能力高的人获胜,否则两个人都获胜,问最后有多少人获胜了.(注:如果他如果有人可以击败他,则就不算获胜) 代码:从代码里面我们看出,先对n个选手的能力值排序,然后ct…

2016暑假多校联合---Rikka with Sequence (线段树) Problem Description As we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them: Yuta has an array A with n numbers. Then he make…