312. 戳气球 有 n 个气球,编号为0 到 n-1,每个气球上都标有一个数字,这些数字存在数组 nums 中. 现在要求你戳破所有的气球.每当你戳破一个气球 i 时,你可以获得 nums[left] * nums[i] * nums[right] 个硬币. 这里的 left 和 right 代表和 i 相邻的两个气球的序号.注意当你戳破了气球 i 后,气球 left 和气球 right 就变成了相邻的气球. 求所能获得硬币的最大数量. 说明: 你可以假设 nums[-1] = nums[n]…

戳气球 有 n 个气球,编号为0 到 n-1,每个气球上都标有一个数字,这些数字存在数组 nums 中. 现在要求你戳破所有的气球.每当你戳破一个气球 i 时,你可以获得 nums[left] * nums[i] * nums[right] 个硬币. 这里的 left 和 right 代表和 i 相邻的两个气球的序号.注意当你戳破了气球 i 后,气球 left 和气球 right 就变成了相邻的气球. 求所能获得硬币的最大数量. 说明: 你可以假设 nums[-1] = nums[n] = 1,…

题目链接 有 n 个气球,编号为0 到 n-1,每个气球上都标有一个数字,这些数字存在数组 nums 中. 现在要求你戳破所有的气球.每当你戳破一个气球 i 时,你可以获得 nums[left] * nums[i] * nums[right] 个硬币. 这里的 left 和 right 代表和 i 相邻的两个气球的序号.注意当你戳破了气球 i 后,气球 left 和气球 right 就变成了相邻的气球. 求所能获得硬币的最大数量. 说明: 你可以假设 nums[-1] = nums[n] = 1…

参考:LeetCode 312. Burst Balloons(戳气球) java代码如下 class Solution { //参考:https://blog.csdn.net/jmspan/article/details/51208865 public int maxCoins(int[] nums) { int[] balls = new int[nums.length+2]; balls[0] = 1; balls[balls.length - 1] = 1; int[][] coins…

The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "…

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There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1] Given the total number of courses and a l…