Problem DescriptionA coding contest will be held in this university, in a huge playground. The whole playground would be divided into N blocks, and there would be M directed paths linking these blocks. The i-th path goes from the ui-th block to the v…
Coding Contest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1751    Accepted Submission(s): 374 Problem Description A coding contest will be held in this university, in a huge playground. The…
题目链接:https://www.nowcoder.com/acm/contest/207/G 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5988 时间限制:C/C++ 2秒,其他语言4秒空间限制:C/C++ 262144K,其他语言524288K64bit IO Format: %lld题目描述 A coding contest will be held in this university, in a huge playground. Th…
Coding Contest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2653    Accepted Submission(s): 579 Problem Description A coding contest will be held in this university, in a huge playground. The…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1533 On a grid map there are n little men and n houses. In each unit time, every little man can move one unit step, either horizontally, or vertically, to an adjacent point. For each little man, you need…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3667 思路:由于花费的计算方法是a*x*x,因此必须拆边,使得最小费用流模板可用,即变成a*x的形式.具体的拆边方法为:第i次取这条路时费用为(2*i-1)*a (i<=5),每条边的容量为1.如果这条边通过的流量为x,那正好sigma(2*i-1)(1<<i<<x)==x^2.然后就是跑最小费用最大流了. #include<iostream> #include<…
Tour Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 2925    Accepted Submission(s): 1407 Problem Description In the kingdom of Henryy, there are N (2 <= N <= 200) cities, with M (M <= 30000…
Special Fish Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2189    Accepted Submission(s): 826 Problem Description There is a kind of special fish in the East Lake where is closed to campus of…
Going Home Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3125    Accepted Submission(s): 1590 Problem Description On a grid map there are n little men and n houses. In each unit time, every…
这就是一道最小费用最大流问题 最大流就体现到每一个'm'都能找到一个'H',但是要在这个基础上面加一个费用,按照题意费用就是(横坐标之差的绝对值加上纵坐标之差的绝对值) 然后最小费用最大流模板就是再用最短路算法找最小费用路径.然后在找到这条路径上面的最大流..就这样一直找下去 代码: 1 //这是一个最小费用最大流问题 2 //最大费用最小流只要在添加边的时候换一下位置就好了 3 //求最大费用最大流只需要把费用换成相反数,用最小费用最大流求解即可 4 #include <cstdio> 5…