WisKey的眼神 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2059    Accepted Submission(s): 625 Problem Description WisKey的眼镜有500多度,所以眼神不大好,而且他有个习惯,就是走路喜欢看着地(不是为了拣钱哦^_^),所以大家下次碰见他的时候最好主动打下招呼,呵呵.但是…

Lifting the Stone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5203    Accepted Submission(s): 2155 Problem Description There are many secret openings in the floor which are covered by a big…

GCC Time Limit: 1000MS Memory limit: 65536K 题目描述 The GNU Compiler Collection (usually shortened to GCC) is a compiler system produced by the GNU Project supporting various programming languages.  But it doesn’t contains the math operator “!”. In math…

 FZU 2110  Star Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u  Practice Description Overpower often go to the playground with classmates. They play and chat on the playground. One day, there are a lot of stars in the sk…

The area Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6524    Accepted Submission(s): 4578题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1071 Problem Description Ignatius bought a land last w…

题目链接:http://lightoj.com/volume_showproblem.php?problem=1385 题意:下图中已知面积 a b c 求 d; 如果d的面积不确定,输出-1. 连接AX,记△AFX的面积为m,△AEX的面积为n. 因为△AFX与△BFX共高线,所以m/a = AF/FB; 又因为(n+c)与b共底边,高线所在的三角形相似,高线只比为AF/FB = (n+c)/b = m/a. 同理可得(m+a)/b = n/c = AE/CE 然后解二元一次方程组求得 m =…

描述 9月10日教师节,也是YuYu的生日,妈妈给YuYu准备了一个很大的圆形蛋糕,YuYu看中了蛋糕中间那诱人的樱桃(都挤到一块啦),小家伙很高兴,心里开始盘算着如何将樱桃全部分给自己.YuYu是个“孝顺”的孩子,汗~~,每次自己不喜欢吃的都是很客气的多分点给爸妈吃,而且一定要事先尝一下(生怕爸妈吃到嘴里烫着O(∩_∩)O哈哈~),因此她开始很积极的分蛋糕了.为了简化问题,我们假设所有的樱桃合起来半径为0,即不考虑其大小.现在家里有4个人,除了一家3口,还有朋友的孩子Ayao.YuYu先在蛋糕…

描述 是否存在面积为S/2的整点锐角三角形?存在输出Yes并输出三个整点坐标,否则输出No. 注意如果存在输出的坐标必须在long long范围内. Input 第一行一个整数S(1<=S<=1018),表示锐角三角形面积. Output 第一行一个字符串. 若存在接下去三行,每行两个整数X,Y,表示三角形三个点的坐标. Examples input 9 output Yes 0 0 3 0 1 3 input 3 output Yes 1 0 0 1 2 2 题意 如上 题解 首先1和2不行…

Mindis Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2787    Accepted Submission(s): 555Special Judge Problem Description The center coordinate of the circle C is O, the coordinate of O is (0,…

http://acm.hdu.edu.cn/showproblem.php?pid=1798 给你两个圆求阴影部分的面积 求出两个扇形的面积减去四边形的面积 扇形的面积是度数(弧度制)*半径的平方 不能用PI 3.1415926   要用acos(-1.0); 求四边形面积就是两个三角形   用海伦公式 因为精确度比较高   所以就不能用PI 3.1415926 #include <iostream> #include <cstring> #include <algorith…