Merge Two Sorted Lists leetcode java】的更多相关文章

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 使用分治法,时间复杂度是nlogk, n是所有元素个数的总和,k是k个lists, 这种方法和依次merge每一个list的方法的时间复杂度不同. 如果第一个list有n-k个元素,其余每个list是1个元素, 两两分治合并,每个元素参与了logk次合并, 如果是依次合并(第一个和第二个合并,之后的结…
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题解: 这道题是链表操作题,题解方法很直观. 首先,进行边界条件判断,如果任一一个表是空表,就返回另外一个表. 然后,对于新表选取第一个node,选择两个表表头最小的那个作为新表表头,指针后挪. 然后同时遍历…
目录 题目链接 注意点 解法 小结 题目链接 Merge Two Sorted Lists - LeetCode 注意点 两个链表长度可能不一致 解法 解法一:先比较两个链表长度一致的部分,多余的部分直接加进答案链表即可.时间复杂度为O(n) /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL)…
Question 23. Merge k Sorted Lists Solution 题目大意:合并链表数组(每个链表中的元素是有序的),要求合并后的链表也是有序的 思路:遍历链表数组,每次取最小节点 Java实现: public ListNode mergeKLists(ListNode[] lists) { ListNode preHead = new ListNode(0); ListNode minNode = getMinNode(lists); ListNode tmpNode =…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. https://leetcode.com/problems/merge-two-sorted-lists/ 题意就是合并两个有序的链表,说实话,这个题我一开始还真有点轻视,不就是merge sort里一步么,但是真写…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Summary:  Finds the smallest node every round, then links it to the one sorted list. ListNode *mergeKLists(vector<ListNode *> &lists) { ListNode *…
题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 翻译 合并k个有序的链表 Hints Related Topics: LinkedList, Divide and Conquer, Heap Solution1:Divide and Conquer 参考 归并排序-维基百科 思路:分治,先分成两个子任务,然后递归子任务,最后回溯回来..这里就…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路一: 之前我们有mergeTwoLists(ListNode l1, ListNode l2)方法,直接调用的话,需要k-1次调用,每次调用都需要产生一个ListNode[],空间开销很大.如果采用分治的思想,对相邻的两个ListNode进行mergeTwoLists,每次将规模减少一半,直到…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相似Merge Sorted Array,仅仅是数据结构由数组换成了链表而已,代码写起来反而更简洁.具体思想就是新建一个链表,然后比较两个链表中的元素值,把较小的…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相…