桌上有 n 堆力扣币,每堆的数量保存在数组 coins 中.我们每次可以选择任意一堆,拿走其中的一枚或者两枚,求拿完所有力扣币的最少次数. 示例 1: 输入:[4,2,1] 输出:4 解释:第一堆力扣币最少需要拿 2 次,第二堆最少需要拿 1 次,第三堆最少需要拿 1 次,总共 4 次即可拿完. 示例 2: 输入:[2,3,10] 输出:8 限制: 1 <= n <= 4 1 <= coins[i] <= 10 来源:力扣(LeetCode) 链接:https://leetcode…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 替换 日期 题目地址:https://leetcode-cn.com/problems/na-ying-bi/ 题目描述 桌上有 n 堆力扣币,每堆的数量保存在数组 coins 中.我们每次可以选择任意一堆,拿走其中的一枚或者两枚,求拿完所有力扣币的最少次数. 示例 1: 输入:[4,2,1] 输出:4 解释:第一堆力扣币最少需要拿 2 次,第二堆最少…

题目描述 桌上有 n 堆力扣币,每堆的数量保存在数组 coins 中.我们每次可以选择任意一堆,拿走其中的一枚或者两枚,求拿完所有力扣币的最少次数. 示例 1: 输入:[4,2,1] 输出:4 解释:第一堆力扣币最少需要拿 2 次,第二堆最少需要拿 1 次,第三堆最少需要拿 1 次,总共 4 次即可拿完. 示例 2: 输入:[2,3,10] 输出:8 限制: 1 <= n <= 4 1 <= coins[i] <= 10 1.思路 一个简单的贪心,每次都拿2个,如果不够两个就拿一个…

You have a total of n coins that you want to form in a staircase shape, where every k-th row must have exactly k coins. Given n, find the total number of full staircase rows that can be formed. n is a non-negative integer and fits within the range of…

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin. Note: You can assume that…

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins,…

Given an array A (index starts at 1) consisting of N integers: A1, A2, ..., AN and an integer B. The integer Bdenotes that from any place (suppose the index is i) in the array A, you can jump to any one of the place in the array A indexed i+1, i+2, ……

小A 和 小B 在玩猜数字.小B 每次从 1, 2, 3 中随机选择一个,小A 每次也从 1, 2, 3 中选择一个猜.他们一共进行三次这个游戏,请返回 小A 猜对了几次? 输入的guess数组为 小A 每次的猜测,answer数组为 小B 每次的选择.guess和answer的长度都等于3. 示例 1: 输入:guess = [1,2,3], answer = [1,2,3] 输出:3 解释:小A 每次都猜对了. 示例 2: 输入:guess = [2,2,3], answer = [3,2,…

题目解析: 对于本题主要的核心是对于一个指令字符串如“RURUU”,如果我们假设它的终点坐标为(8,8),其实只要统计指令字符串中的R的个数和U的个数(对于我给出的例子而言,num_R == 2,num_U == 3),显然不管我们是否能到达终点,这条指令至少要走不止一遍才有可能,那么我们只要将它在达到终点前必走的x轮减去(对于我给出的例子而言x == min(8 / 2 ,8 / 3)== 2,则忽略中间走的轮数,就能把终点的位置转化为(4,2)),则就能求出最后那不足一轮的情况下需要U多少个…

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin. Note: You can assume that…