104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB 问题: 你想要将你的花窗安排得最具美感.有F束花,每一束花都不一样,至少有F个按顺序排成一行的花瓶.花瓶从左到右,依次编号1-V.而花放置的位置是可以改变的,花依次编号1到F.花的序号有一个特征,即是序号决定了花束出现在花瓶里的顺序.例如,有两束花编号i和j,满足i<j,那么i所在的花瓶一定要在j所在花瓶的左边,即是i…

104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB PROBLEM You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least a…

花店橱窗布置问题 时间限制:3000 ms 问题描述(Problem)    假设你想以最美观的方式布置花店的橱窗,你有F束花,每束花的品种都不一样,同时,你至少有同样数量的花瓶,被按顺序摆成一行.花瓶的位置是固定的,并从 左至右,从1至V顺序编号,V是花瓶的数目,编号为1的花瓶在最左边,编号为V的花瓶在最右边.花束则可以移动,并且每束花用1至F的整数唯一标识.标识 花束的整数决定了花束在花瓶中排列的顺序,即如果i<j,则花束i必须放在花束j左边的花瓶中.    例如,假设社鹃花的标识数为1,秋…

浪(吃)了一天,水道题冷静冷静.... 题目链接: http://acm.sgu.ru/problem.php?contest=0&problem=104 题意: 给定每朵花放在每个花盆的值,编号大的花只能放在编号小的花的后面,每朵花都要放到花盆里,问如何放才能使得总值最大? 分析: 还是一道比较水的dp... 每个位置有两种情况:放与不放. 不放的话\(dp[i][j-1][0]\)就等于前面最近的放了花盆的值. 放的话,就更新\(dp[i][j][1]\). 这样保证对于每个花盆\(i\)花…

经典dp问题,花店橱窗布置,不再多说,上代码 #include <cstdio> #include <cstring> #include <iostream> #include <cstdlib> #include <algorithm> #define N 150 #define inf 0x7f7f7f7f using namespace std; int n, m; int val[N][N], f[N][N]; int fa[N][N];…

104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB PROBLEM You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least a…

104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB PROBLEM You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least a…

LITTLE SHOP OF FLOWERS Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 19877 Accepted: 9153 Description You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kin…

[POJ1157]LITTLE SHOP OF FLOWERS 试题描述 You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least as many vases ordered in a row. The vases are glued onto the s…

题意 每个花按序号顺序放到窗口,不同窗口可有不同观赏值,所有花都要放上去,求最大观赏值和花的位置. 分析 dp,dp[i][j]表示前i朵花最后一朵在j位置的最大总观赏值. dp[i][j]=max(dp[i-1][k]+f[i][j]) 代码 #include<cstdio> #include<algorithm> using namespace std; const int N=105; int n,w,ans=-99999; int dp[N][N],f[N][N],last…