Count the number of occurrences in a sorted array Given a sorted array arr[] and a number x, write a function that counts the occurrences of x in arr[]. Expected time complexity is O(Logn) Examples: Input: arr[] = {1, 1, 2, 2, 2, 2, 3,}, x = 2 Output…
Let's say we are going to find out number of occurrences of a number in a sorted array using binary search in O(log n) time. For example the given array is: [1,1,3,5,5,5,5,5,9,11], the number 5 appears 5 times; the number 3 appears 1 time; 2 appears…
If you want to see the number of threads per process in Linux environments, there are several ways to do it. Method One: /proc The proc pseudo filesystem, which resides in /proc directory, is the easiest way to see the thread count of any active proc…
Description Given n numbers, your task is to insert '+' or '-' in front of each number to construct expressions. Note that the position of numbers can be also changed. You can calculate a result for each expression. Please count the number of distinc…
题目如下: Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is unique. Example 1: Input: arr = [1,2,2,1,1,3] Output: true Explanation: The value 1 has 3 occurrences, 2 h…
 实现一个函数clone,可以对JS中的5种数据类型(Number.String.Object.Array.Boolean)进行值复制…
实现一个函数clone,可以对JavaScript中的5种主要的数据类型(包括Number.String.Object.Array.Boolean)进行值复制. 1 /** 对象克隆 2 * 支持基本数据类型及对象 3 * 递归方法 */ 4 function clone(obj) { 5 var o; 6 switch (typeof obj) { 7 case "undefined": 8 break; 9 case "string": o = obj + &q…
From: http://www.geeksforgeeks.org/find-number-of-triangles-possible/ Given an unsorted array of positive integers. Find the number of triangles that can be formed with three different array elements as three sides of triangles. For a triangle to be…
有时候在项目中我们需要检测当前连接在机子上的摄像头的数量,可以通过下面的代码实现,其中连接摄像头的最大数量maxCamNum可以任意修改: /** * Count current camera number */ int countCamera() { ; ; ; device < maxCamNum; device++) { CvCapture* capture; if (_capture[device]) { ++count; } else { capture = cvCaptureFrom…
青蛙跳跳: package com.code; public class Test03_1 { public int solution(int X, int Y, int D) { int res = (Y-X)/D+((Y-X)%D==0?0:1); return res; } public static void main(String[] args) { Test03_1 t03 = new Test03_1(); System.out.println(t03.solution(10, 8…