hdu 2647 Reward

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ACM: hdu 2647 Reward -拓扑排序

hdu 2647 Reward Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble…

HDU.2647 Reward(拓扑排序 TopSort)

HDU.2647 Reward(拓扑排序 TopSort) 题意分析裸的拓扑排序详解请移步算法学习拓扑排序(TopSort) 这道题有一点变化是要求计算最后的金钱数.最少金钱值是888,最少的差额是1,如1号的人比2号钱要多,2号至少是1号人的钱数+1.根据拓扑排序的思想,我们只需要类比二叉树的层序遍历,每次取出入度为0的节点做处理,累加金钱数量,然后再取出入度为0的节点处理.直到取出所有的点或者判断成环即可. 代码总览 #include <iostream> #include <…

题解报告：hdu 2647 Reward（拓扑排序）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2647 Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewar…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2647 Reward Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the reward…

HDU 2647 Reward (拓扑排序)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2647 题意是给你n点m条有向边,叶子点(出度为0)上的值为888,父亲点为888+1,依次计算... 让你求最小的值,但是中间出现有向环就不行了,输出-1. 拓扑排序队列实现,因为叶子是最小的,所以把边反向就可以求了. //拓扑队列实现 //就是先把入度为0的先入队,然后每次出队的时候把相邻的点的入度减1,要是入度为0则再入队,不断循环直到队列为空 //时间复杂度为O(N + E) //这题就是把边…

HDU 2647 Reward（拓扑排序+判断环+分层）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2647 题目大意:要给n个人发工资,告诉你m个关系,给出m行每行a b,表示b的工资小于a的工资,最低工资为888,求最少要发多少工资,如果关系矛盾就输出“-1”. 解题思路:用拓扑排序解决,但是要分层,类似于多棵树的层次遍历,用dis[i]存储i所在层数(起点为0层),因为要是所有条件都符合,所以dis[i]取最大值.还有注意判断是否存在环. 代码: #include<iostream> #inc…

HDU 2647 Reward（图论-拓扑排序）

Reward Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewards. The workers will compare their rewards ,a…