题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2087 题目大意:给你一个字符串,求出将字符串的最少出现两次循环节需要添加的字符数. 解题思路: 这题需要利用next数组的性质,求出字符串的最小循环节 有几个结论(具体可以看这里http://www.cnblogs.com/wuyiqi/archive/2012/01/06/2314078.html): ①字符串长度为len,则len-next[len]为最小循环节. ②如果len%(len-nex…

思路: 最小循环节的解释在这里,有人证明了那么就很好计算了 之前对KMP了解不是很深啊,就很容易做错,特别是对fail的理解 注意一下这里getFail的不同含义 代码: #include<iostream> #include<algorithm> const int N = 1000000+5; const int INF = 0x3f3f3f3f; using namespace std; int fail[N]; char p[N],t[N]; void getFail(){…

题意: 求最少需要在后面补几个字符能凑成两个循环. 分析: 最小循环节的应用,i-next[i]为最小循环节. #include <map> #include <set> #include <list> #include <cmath> #include <queue> #include <stack> #include <cstdio> #include <vector> #include <strin…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11516    Accepted Submission(s): 4913 Problem Description CC always becomes very depressed at the end of this month, he has checke…

题意:给出一串字符串,可以在字符串的开头的结尾添加字符,求添加最少的字符,使这个字符串是循环的(例如:abcab 在结尾添加1个c变为 abcabc 既可). 思路:求出最小循环节,看总长能不能整除. #include<iostream> #include<stdio.h> #include<string.h> using namespace std; #define MaxSize 100005 int _next[MaxSize]; void GetNext(cha…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13790    Accepted Submission(s): 5738 Problem Description CC always becomes very depressed at the end of this month, he has check…

Cyclic Nacklace Problem's Link: http://acm.hdu.edu.cn/showproblem.php?pid=3746 Mean: 给你一个字符串,让你在后面加尽量少的字符,使得这个字符串成为一个重复串. 例: abca---添加bc,成为abcabc abcd---添加abcd,成为abcdabcd aa---无需添加 analyse: 经典的求最小循环节. 首先给出结论:一个字符串的最小循环节为:len-next[len]. 证明: 举个例子:abcab…

Cyclic Nacklace Problem Description CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14416    Accepted Submission(s): 6016 Problem Description CC always becomes very depressed at the end of this month, he has checke…

题目链接:HDU 3746 Sample Input 3 aaa abca abcde Sample Output 0 2 5 Author possessor WC Source HDU 3rd "Vegetable-Birds Cup" Programming Open Contest Solution 题意 给定一个字符串,问至少需要在末尾添加多少个字符使得字符串循环. 思路 KMP 设前缀函数为 \(\pi()\),字符串长度为 \(n\),下标从 \(1\) 开始. 最小循环…

Cyclic Nacklace 题意:给一个长度为Len( 3 <= Len <= 100000 )的英文串,问你在字符串后面最少添加几个字符可以使得添加后的串为周期串? Sample Input 3 aaa abca abcde   Sample Output 0 2 5   思路:要是写过period再来写这道题会发现很简单:就是在getfail()得到f[]之后,贪心地看最后一个字符所能用到的最长后缀长度为多少?而这个后缀长度就是n - n%len;(n为字符串长度,len为循环节的长度…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2716    Accepted Submission(s): 1244 Problem Description CC always becomes very depressed at the end of this month, he has checked…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4212    Accepted Submission(s): 1913 Problem Description CC always becomes very depressed at the end of this month, he has checked…

题意: 给一个字符串,问:要补多少个字符才能让其出现循环?出现循环是指循环节与字符串长度不相等.比如abc要补多个变成abcabc.若已经循环,输出0. 思路: 根据最小循环节的公式,当len%(len-next[len])==0时,最小循环节为len/(len-next[len]),而当len%(len-next[len])!=0时,就没有循环节.可以通过在串尾补上一些字符,使得len%(len-next[len])==0,就会出现循环节了. #include <bits/stdc++.h>…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3746 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description CC always becomes very depressed at the end of this month, he has checked his credit card yesterd…

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=3746 KMP算法—— AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <string> #include <vector> #include <list&…

Problem Description CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the last days. Bein…

<题目链接> 题目大意: 给你一个字符串,要求将字符串的全部字符最少循环2次需要添加的字符数. [>>>kmp next函数 kmp的周期问题]  #include <cstdio> #include <cstring> + ; char s[maxn]; int Next[maxn]; void get_next() { , k = -; Next[] = -; while (s[j]) { || s[j] == s[k]) Next[++j] =…

//len-next[len]为最小循环节的长度 # include <stdio.h> # include <algorithm> # include <string.h> using namespace std; int len; char a[100010]; int next[100010]; void Getnext() { int i=0,j=-1; next[0]=-1; while(i<=len) { if(j==-1||a[i]==a[j]) i…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3746 思路:KMP中Next数组的应用,求出最小的循环节,题目的意思是只能在字符串的后面上添加新的字符凑成两个循环节 用Next数组来求最小循环节的方法见这:http://www.cnblogs.com/wuyiqi/archive/2012/01/06/2314078.html #include<string.h> #include<stdio.h> #include<iost…

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10685    Accepted Submission(s): 4583 Problem Description CC always becomes very depressed at the end of this month, he has checked his credit car…

HDU 3374 String Problem (KMP+最大最小表示) String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1602    Accepted Submission(s): 714 Problem Description Give you a string with length N, you c…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4420    Accepted Submission(s): 2011 Problem Description CC always becomes very depressed at the end of this month, he has checked…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2538    Accepted Submission(s): 1154 Problem Description CC always becomes very depressed at the end of this month, he has checke…

http://acm.hdu.edu.cn/showproblem.php?pid=3746 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 9975    Accepted Submission(s): 4267 Problem Description CC always becomes very depressed at the e…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 39408    Accepted Submission(s): 16269 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

题目代号:HDU 1711 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 28288    Accepted Submission(s): 11891 Problem Description Give…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=2328 题意:多组输入,n==0结束.给出n个字符串,求最长公共子串,长度相等则求字典序最小. 题解:(居然没t,可能数据水了吧)这个题和 HDU - 1238 基本一样,用string比较好操作.选第一个字符串然后两层循环(相当于找到所有的子串),然后和其他几个字符串比较看是否出现过,如果所有字符串中都出现了就记录下来,找出长度最大字典序最小的子串.否则输出"IDENTITY LOST".…

String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2706    Accepted Submission(s): 1140 Problem Description Give you a string with length N, you can generate N strings by left shift…

Another Meaning 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5763 Description As is known to all, in many cases, a word has two meanings. Such as "hehe", which not only means "hehe", but also means "excuse me". Today, ?? i…