题目链接:http://202.197.224.59/OnlineJudge2/index.php/Problem/read/id/1252 思路:考虑每条边对玩家的伤害 假设连接的节点是u,v,破坏力是p[u]和p[v] 假设p[u]>p[v] 现在考虑u,v的删除顺序,如果先删u,这条边对玩家的伤害,是p[v],先删v,伤害是p[u] 所以显然对于每条边,我们都要先删权值大的,才能最好 怎么样才能对于每条边先删最大的呢,那就按照权值递减删就好了 所以 ret=Σ(min(p[u],p[v])…

$2016$长城信息杯中国大学生程序设计竞赛中南邀请赛$J$题 贪心. 优先删除$power$大的点. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #include<map>…

地址 注意思路!多看几遍! 很巧妙的一道题.不再是决策点以dp值中一部分含j项为维护对象,而是通过维护条件来获取决策. 首先有个贪心策略,让底层的宽度尽可能小,才能让高度尽可能高.所以应该倒着dp,表示堆$i$~$n$的最高高度$f[i]$,同时这种最值应来源于之后的j,要在设一个$g[i]$表示以i为底层,最窄的宽度.这个的话真的只可意会啊.注意$g[i]$没人告诉你是单调的,$g[i]$之后一个不合法的决策都可能有$g[j]>g[i]$,所以单调性问题还当谨慎考虑. 所以dp方程就能出来了…

Battle Ships Time Limit: 2 Seconds      Memory Limit: 65536 KB Battle Ships is a new game which is similar to Star Craft. In this game, the enemy builds a defense tower, which has L longevity. The player has a military factory, which can produce N ki…

Battle Ships is a new game which is similar to Star Craft. In this game, the enemy builds a defense tower, which has L longevity. The player has a military factory, which can produce N kinds of battle ships. The factory takes tiseconds to produce the…

B - Battle Ships Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Submit Status Practice ZOJ 3623 Appoint description:   Description Battle Ships is a new game which is similar to Star Craft. In this game, the enemy builds a…

传送门Battle Ships Time Limit: 2 Seconds      Memory Limit: 65536 KB Battle Ships is a new game which is similar to Star Craft. In this game, the enemy builds a defense tower, which has L longevity. The player has a military factory, which can produce N…

Battle Ships is a new game which is similar to Star Craft. In this game, the enemy builds a defense tower, which has L longevity. The player has a military factory, which can produce N kinds of battle ships. The factory takes ti seconds to produce th…

Stupid Tower Defense Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1219    Accepted Submission(s): 361 Problem Description FSF is addicted to a stupid tower defense game. The goal of tower…

2014多校7 第二水的题 4939 Stupid Tower Defense Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 366    Accepted Submission(s): 88 Problem Description    FSF is addicted to a stupid tower defense gam…

Problem Description FSF is addicted to a stupid tower defense game. The goal of tower defense games is to try to stop enemies from crossing a map by building traps to slow them down and towers which shoot at them as they pass. The map is a line, whic…

Tower Defense Toolkit 做塔防游戏的插件 主要层次如下图: 1GameControl _ _Game Control(Script) _ _ _Spawn Manager _ _ _Range Indicator H _ _ _ Range Indicator F _ _Layer Manager(Script) _ _Resource Manager(Script) 2BuildManager _ _Build Manager(Script) _ _ _Towers _ _…

Stupid Tower Defense Time Limit: 12000/6000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1557 Accepted Submission(s): 445 Problem Description FSF is addicted to a stupid tower defense game. The goal of tower defen…

Tower Defense Game 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 There is a tower defense game with n levels(missions). The n levels form a tree whose root is level 1. In the i-th level, you have to spend pi units of money buying towers and after the level,…

Tower Defense Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 132768/132768 K (Java/Others) Total Submission(s): 474    Accepted Submission(s): 126 Problem Description DRD loves playing computer games, especially Tower Defense games. Tower De…

/** 题目:2016-2017 ACM-ICPC CHINA-Final Ice Cream Tower 链接:http://codeforces.com/gym/101194 题意:给n个木块,堆一个小塔要k个木块,满足相邻两个木块,上面的木块大小至少是下面的木块的两倍. 问最多可以堆出几个小塔. 思路:二分+贪心. 先二分最终可以堆出的小塔数x,然后确定了数量,就可以这样来贪心,把前x个木块作为所有小塔的顶部木块, 然后从剩下的木块中继续取前x小的,从小到大放在x个小塔的次顶部,然后继续.…

题目链接: D. Bear and Tower of Cubes time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a little polar bear. He plays by building towers from blocks. Every block is a cube with positive…

Tower Defense Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 132768/132768 K (Java/Others)Total Submission(s): 1025    Accepted Submission(s): 297 Problem Description DRD loves playing computer games, especially Tower Defense games. Tower De…

题目: Mr. Panda likes ice cream very much especially the ice cream tower. An ice cream tower consists of K ice cream balls stacking up as a tower. In order to make the tower stable, the lower ice cream ball should be at least twice as large as the ball…

题目链接:https://hihocoder.com/problemset/problem/1199. 题意:一棵以1为根的树,每个点有一个p值和q值,到这个点需要当前分数大于等于p,然后消耗掉(p-q)的分数.问一种遍历方式,使得一开始在1所需的分数最小并能够遍历完所有的点. 分析见代码: #include <stdio.h> #include <algorithm> #include <string.h> #include <vector> using…

题目链接: http://codeforces.com/gym/101194/attachments https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=5922 题意: 给出 $N$ 个冰淇淋球,第 $i$ 个冰淇淋球大小为 $B_i$,现在已知冰淇淋球堆叠起来可组成一个冰淇淋. 对于上下相邻的两个冰淇淋球,只有上面的那个大小不…

题目链接 : https://cn.vjudge.net/problem/Gym-101194D 题目大意 : 给你n个冰激凌球,让你用这些冰激凌球去垒冰激凌,要求是下面的这一个必须是他上面一个的两倍大,一个冰激凌需要m个冰激凌,问你最多能造几个冰激凌. 具体思路: 贪心 + 二分 ,首先对输入的n个冰激凌球进行排序,从小到大开始,然后对答案进行二分,从当前的开始,找第一个满足的,然后找完一个再继续找下一个,如果当前要检测的答案是k,那么就需要找k层满足情况的． AC代码: #include<b…

题目大意: 一个$n(n\le5\times10^5)$个点$m(m\le10^6)$条边的无向图,边权全为$1$,满足若一个标记点能覆盖与其距离不超过$1$的点,从中选取不超过$k$个点能将整张图覆盖.问若一个标记点能覆盖与其距离不超过$2$的点,求构造一种选取点数不超过$k$的方案将整张图覆盖. 思路: 贪心,每次选取没有覆盖的点作为标记点,并更新覆盖点的和.选取一个点后增加的覆盖范围一定完全包含原来覆盖这个点的标记点的覆盖范围,因此方案一定更优. #include<cstdio> #in…

链接 Codeforces 680D Bear and Tower of Cubes 题意 求一个不超过 \(m\) 的最大体积 \(X\), 每次选一个最大的 \(x\) 使得 \(x^3\) 不超过当前剩余体积.问在能选最多个数的情况下,\(X\) 最大是多少 思路 对于每一次选择,首先要保证选完后的剩余体积最大,这样就保证了能选最多个数.然后在这基础上保证 \(X\) 最大. 考虑对于最大的 \(a\),使得 \(a^3<=m\). 如果当前选择的是 \(a\),则剩余体积就是 \(m1…

题目大意: 对于给出的n个冰激凌球的大小,满足下面的球的大小是上一个的至少2倍,对于给出的k(由k的冰激凌球才能算作一个冰激凌塔),问n个冰激凌球可以最多堆出多少个高度为k的冰激凌塔 题目分析: 对于n个冰激凌球,显然我们得知可以堆出的高度为k的塔的数量在0~[n / k]之间,这里可以通过二分遍历每一种可能,初始时二分边界l==0,r==[n / k],每次取中间值mid=(l+r)/ 2,判断mid高度为k的塔能否堆出,如果可以则尝试mid为更大,否则则尝试mid为更小时,不断二分尝试mid…

意思是有个塔防游戏,有三种塔,红塔在怪物经过的时候每秒会产生攻击力大小的伤害,绿塔对怪物经过以及经过之后每秒产生攻击力大小的伤害,还有种蓝塔,对怪物进行减速,即怪物从此之后经过一个单位都会减慢c秒 最后最最大的伤害值是多少 又是比赛的时候没想出来,知道是个DP,但是对这种多变量型的DP就是有点不感冒.这个思想其实也是差不多的,你首先得枚举其中的一个值或者两个值 这里有个特性,我绿塔和蓝塔放越前面越好,红塔放越后面越好(主要是腾前面的位置给另外两种),这用了点贪心技巧,但绝对是对的 所以我们可以枚…

https://ac.nowcoder.com/acm/contest/1072/B Description 为了调整电灯亮度,贝西要用干草包堆出一座塔,然后爬到牛棚顶去把灯泡换掉.干草包会从传送带上运来,共会出现N包干草,第i包干草的宽度是Wi,高度和长度统一为1.干草塔要从底层开始铺建.贝西会选择最先送来的若干包干草,堆在地上作为第一层,然后再把紧接着送来的几包干草包放在第二层,再铺建第三层……重复这个过程,一直到所有的干草全部用完.每层的干草包必须紧靠在一起,不出现缝隙,而且为了建筑稳定,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4939 解题报告:一条长度为n的线路,路上的每个单元格可以部署三种塔来给走在这条路上的敌人造成伤害,第一种塔只给在这个塔的范围内的敌人每秒造成x点的伤害,第二种塔给已经经过过这个塔的敌人每秒造成y点伤害,第三种塔能使已经经过了这个塔的敌人的前进的速度减慢,具体效果是,原来敌人经过一个单元格的时间是t秒,经过减速后,经过每个单元格的时间是t + z,这个一个塔减速的效果,减速的效果可以叠加,同样,第二种…

思路:首先红色肯定要放在最后面.前面蓝色和绿色dp求解. dp[i][j]  表示前面(i+j) 个 有 i 个蓝色塔  j个绿色塔 能造成最大伤害. //============================================================================ // Name : 1005.cpp // Author : // Version : // Copyright : Your copyright notice // Description…

题目链接 题意 :长度n单位,从头走到尾,经过每个单位长度需要花费t秒,有三种塔: 红塔 :经过该塔所在单位时,每秒会受到x点伤害. 绿塔 : 经过该塔所在单位之后的每个单位长度时每秒都会经受y点伤害. 蓝塔 : 经过该塔所在单位之后,再走每个单位长度的时候时间会变成t+z. 思路 : 官方题解 : #include <cstdio> #include <cstring> #include <iostream> #define LL long long using na…