新建一个JavaProject(不一定非要web工程) 在工程里面新建一个文件夹lib,用来存放jar包 找到Hibernate的下载文件,解压后找到required文件夹,这是需要的jar包 添加到咱们建好的lib文件夹里面 Hibernate下载地址http://hibernate.org/orm/downloads/ 还需要的就是jdbc驱动包 mysql-connector-java-5.1.37-bin.jar 下载地址http://www.mysql.com/products/con…

    把 common/config/main-local.php 下的 mailer 注释掉:           'mailer'=>[                    'class'=>'yii\swiftmailer\Mailer',                    'viewPath'=>'@common/mail',                    'useFileTransport'=>false,                    'tran…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

题目简述 Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spac…

Given a non-empty string s and an abbreviation abbr, return whether the string matches with the given abbreviation. A string such as "word" contains only the following valid abbreviations: ["word", "1ord", "w1rd", &…

一.引言: 在storm发布到0.9.x以后,配置storm将会变得简单很多,也就是只需要配置zookeeper和storm即可,而不再需要配置zeromq和jzmq,由于网上面的storm配置绝大部分都是0.9以前的storm版本,所以有很多工作是不需要进行的,下面就storm的0.9.5版本在linux环境下进行配置进行详细解析. 由于配置storm只需要两个步骤,大大简化了配置,也是storm团队做了很大的努力,让程序员们专注于程序,让storm配置进行异常简单,好了,废话说了不少,下面正…

组合数学....和上一题是一样的.... Word Index Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 4303 Accepted: 2439 Description Encoding schemes are often used in situations requiring encryption or information storage/transmission economy. Here, we develo…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Notice A word is defined as a character sequence consists of non-space ch…

Word Ladder Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example,…

Word Search Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell m…

题目: Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given: start =…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. Example…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

题目: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Length of Last Word Total Accepted: 47690 Total Submissions: 168587     Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. N…

leetcode: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

题目: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space…

题目描述: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spa…

题目: Design a data structure that supports the following two operations: void addWord(word) bool search(word) search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one le…

using System;using System.Collections.Generic;using System.Text;using Microsoft.Office.Interop.Word;using System.IO;using System.Web;using System.Data;using System.Reflection;using Microsoft.Win32;using System.Text.RegularExpressions;using System.Net…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

感冒之后 睡了2天觉 现在痊愈了 重启刷题进程.. Google的题,E难度.. 比较的方法很多,应该是为后面的题铺垫的. 题不难,做对不容易,edge cases很多,修修改改好多次,写完发现是一坨. 奉劝大家尽量多想edge cases,想不出来了再提交,别像我似的赶着投胎就提交了. 想完了先自己试试下面这些test cases... "internationalization" "i12iz4n" "word" "1or1&quo…

原文:我的VSTO之路(三):Word基本知识 在前一篇文章中,我初步介绍了如何如何开发一个VSTO程序,在本文中,我将进一步深入介绍Word的插件开发.Word是一个大家在日常工作中一直接触的文档工具,也是微软最赚钱的产品之一.从最初的Word 1.0到现在的Word 2010历经了13代的演化,已经成为了一个比较复杂的系统.(这里稍微跑题一下,Office 2010的版本代号是version 14,但是我为什么说Word一共演化了13代呢?因为Office并没有Version 13,上一代的…

使用NPOI可以方便的实现服务端对Word.Excel的读写.要实现对Word的读写操作,需要引用NPOI.OOXML.dll,应用命名空间XWPF. 本文使用NPOI 2.0实现对Word的基本生成.下载操作. NOPI 2.0 下载地址:http://npoi.codeplex.com/downloads/get/764162 虽然现在最新版本为NPOI 2.1.1 ,但笔者使用2.1.1的NPOI.OOXML.dll时,发现无法实现段落格式化功能,故推荐使用本文版本. 需要添加的命名空间:…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Problem Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four wor…