poj1486 Sorting Slides】的更多相关文章

Sorting Slides Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4812   Accepted: 1882 Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transpa…
Sorting Slides Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4442   Accepted: 1757 Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transpa…
Sorting Slides Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 2831   Accepted: 1076 Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transpa…
Sorting Slides Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5390   Accepted: 2095 Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transpa…
Sorting Slides Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4469   Accepted: 1766 Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transpa…
UVA663 Sorting Slides(烦人的幻灯片) 第一次做到这么玄学的题,在<信息学奥赛一本通>拓扑排序一章找到这个习题(却发现标程都是错的),结果用二分图匹配做了出来 蒟蒻感觉思路不太好想,难度大概在蓝题~紫题,至于为什么是黑题.. 那是因为UVa输出换行空格万年老坑 #include<cstdio> #include<cstring> using namespace std; #define N 27 int vis[N],match[N],ans[N],…
Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transparencies on one big heap. Before giving the talk, he has to sort the slides. Being a kind of minima…
Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transparencies on one big heap. Before giving the talk, he has to sort the slides. Being a kind of minima…
题目描述: Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transparencies on one big heap. Before giving the talk, he has to sort the slides. Being a kind of minimalist,…
题意:找出幻灯片与编号唯一对应的情况 思路: 1:求最大匹配,若小于n,则答案为none,否则转2 (不过我代码没有事先判断一开始的最大匹配数是否<n,但这样也过了,估计给的数据最大匹配数一定为n吧) 2:删除一条边e,以e的一个端点找增广路,若不能找到增广路则e是必须边 也就是重新计算匹配数,如果匹配数减少说明此边是必须也是唯一的.    如果一样说明这边存不存在都行.转3 3:恢复原图,继续步骤2,直到每条边都被删除过 刚开始看网上别人的代码,有一点看不懂,那就是为什么只要找到唯一对应的就输…