1. Convert Sorted List to Binary Search Tree Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth…
[LeetCode]109. Convert Sorted List to Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/description/ 题目描述: Given a s…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. (二)解题 本题大意:给定一个单向链表,构造出平衡二叉搜索树 解题思路:参考[一天一道Leet…
Problem Link: http://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ Same idea to Convert Sorted Array to Binary Search Tree, but we use a recursive function to construct the binary search tree. # Definition for a binary tree nod…
1. 题目 1.1 英文题目 Given an integer array nums where the elements are sorted in ascending order, convert it to a height-balanced binary search tree. A height-balanced binary tree is a binary tree in which the depth of the two subtrees of every node never…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/#/description 题目描述 Given an array where elements are sorted in ascending order,…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. (二)解题 题目大意:给定一个排好序的数组,将它转变成一个平衡二叉搜索数 解题思路:平衡二叉搜索树的中序遍历为升序数组…
Problem Link: http://oj.leetcode.com/problems/convert-sorted-list-to-binary-search-tree/ We design a auxilar function that convert a linked list to a node with following properties: The node is the mid-node of the linked list. The node's left child i…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 把一个有序的数组转换为一颗平衡二叉搜索树.每次找到中间节点作为根节点,根节点左边部分转换为左子树,右边部分转换为右子树.代码如下: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNo…
Problem: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Solution: 复习一下BST的基本性质:简而言之,对于BST中任意结点x,若其有左右结点 l 或 r ,需满足 l.key ≤ x.key ≤ r.key BST的性能(基本操作耗时)与树高成正比,可改进为较为高效的平衡二叉树,即保持整棵树左右均匀,任意左右子树高度差不大于1 如…