1005 Spell It Right (20)(20 分) Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English. Input Specification: Each input file contains one test case. Each case occupies one l…

PAT (Advanced Level) Practice 1005 Spell It Right (20 分) 凌宸1642 题目描述: Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English. 译:给出一个非负整数 N , 你的任务是计算出 N 的每位数的和,并且用英语输出和的每一位数…

1005. Spell It Right (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English. Input Specification: E…

1005 Spell It Right (20)(20 分) Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English. Input Specification: Each input file contains one test case. Each case occupies one l…

1005 Spell It Right (20分) 题目: Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English. Input Specification: Each input file contains one test case. Each case occupies one li…

题目链接 https://www.patest.cn/contests/pat-a-practise/1005 思路 因为 n <= 10^100 所以 要用字符串读入 但是 100 * 100 = 10000 所以 sum 用int 保存就好了 再把 sum 的每一位 用 英文输出 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #incl…

题意: 给出一个非零整数N(<=10^100),计算每位之和并用英文输出. AAAAAccepted code: #include<bits/stdc++.h> using namespace std; string s; ][]={"zero","one","two","three","four","five","six","seven&…

上星期一直在写报告乱七八糟的,从今天开始不刷乙级的了,还是多刷甲级进步来得快一点! 显而易见,该题的关键在于将输入之和的每一位从高到低输出,这里我们发现题意中的输入数的范围为0-10^100,显然我们可以使用字符串输入,之后分别遍历每一位,将其分别存入sum中. 因为是从高到低输出每一位,而不是从低到高:若是后者,则可以使用一个小函数不断取余再除以10即可全部输出:此时是前者,则可使用sstream头文件,将sum转换为字符串形式,再分别遍历每一位,输出每一位的值对应的字符数组分量,即可AC.…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<vector> using namespace std; +; char s[maxn]; int tmp[maxn],tot; ][]={ "zero", "one", "two…

把每个位上的数字求和sum,然后以英文单词的形式输出sum的每个位 #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <vector> using namespace std; /* 把每个位上的数字求和sum,然后以英文单词的形式输出sum的每个位 水 */ ][]={"zero","one&…