Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... By considering the terms in the Fibonacci sequence whose values do not…

C. DZY Loves Fibonacci Numbers time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation F1 = 1; F2 …

Fibonacci Numbers Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 81 Accepted Submission(s): 46   Problem Description The Fibonacci sequence is the sequence of numbers such that every element is e…

/** 题目:Colossal Fibonacci Numbers! UVA 11582 链接:https://vjudge.net/problem/UVA-11582 题意:f[0] = 1, f[1] = 1; 给定一个n,求f[a^b]%n的结果.a,b达到2^64 - 1大. 思路:a,b很大,用无符号长整型;我还是太菜了,自己没想出来.这道题很显然是找循环节的题.但我不知怎么找. lrj P316 思路就是,由于fibonacci数是由前两个数相加得来,又%n;所以所有fibonacc…

题目链接: https://projecteuler.net/problem=435 题意: The Fibonacci numbers $ {f_n, n ≥ 0}$ are defined recursively as \(f_n = f_{n-1} + f_{n-2}\) with base cases \(f_0 = 0\) and \(f_1 = 1\). Define the polynomials $ {F_n, n ≥ 0} $ as $F_n(x) =\sum_{i=0}^{n…

In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation F1 = 1; F2 = 1; Fn = Fn - 1 + Fn - 2 (n > 2). DZY loves Fibonacci numbers very much. Today DZY gives you an array consisting of n integers: a1, a2, ...,…

C. DZY Loves Fibonacci Numbers time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation F1 = 1; F2 …

Let d(n) be defined as the sum of proper divisors of n (numbers less than n which divide evenly into n). If d(a) = b and d(b) = a, where a b, then a and b are an amicable pair and each of a and b are called amicable numbers. For example, the proper d…

參考:http://www.cnblogs.com/chanme/p/3843859.html 然后我看到在别人的AC的方法里还有这么一种神方法,他预先设定了一个阈值K,当当前的更新操作数j<K的时候,它就用一个类似于树状数组段更的方法,用一个 d数组去存内容,譬如它要在区间 [3,6]上加一段fibonacci 原来: id 0 1 2 3 4 5 6 7 8 9 10 d  0 0 0 0 0 0 0 0 0 0 0 更新: id 0 1 2 3 4 5 6  7  8  9 10 d  0…

HDU 3117 Fibonacci Numbers(斐波那契前后四位,打表+取对+矩阵高速幂) ACM 题目地址:HDU 3117 Fibonacci Numbers 题意:  求第n个斐波那契数的前四位和后四位.  不足8位直接输出. 分析:  前四位有另外一题HDU 1568,用取对的方法来做的.  后四位能够用矩阵高速幂,MOD设成10000即可了. 代码: /* * Author: illuz <iilluzen[at]gmail.com> * Blog: http://blog.c…