[pat]1068 Find More Coins】的更多相关文章

1068 Find More Coins (30)(30 分) Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a speci…
满背包问题,把体积和价值看成相等的.用滚动数组优化,然后额外开辟一个choice数组来记录每次的选择,然后回溯打印.因为要按字典序,先把价值进行排序.假如选最小的商品能装满m的话,那就把判断条件改成大于等于,然后最后来 #include<bits/stdc++.h> using namespace std; ]; ]; ]; ][]; int n, m; bool cmp(int a, int b) { return a > b; } int main() { memset(flag,…
1068. Find More Coins (30) 时间限制 150 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could ac…
1068 Find More Coins (30 分)   Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special…
一开始没多想,虽然注意到数据N<=10^4的范围,想PAT的应该不会超时吧,就理所当然地用dfs做了,结果最后一组真的超时了.剪枝啥的还是过不了,就意识到肯定不是用dfs做了.直到看到别人说用01背包的思路,果真好久没做题了智力水平下降,且原本dp就是我的弱项,压根就没把这题往dp上去想额... (http://www.liuchuo.net/archives/2323) 题意:从n个硬皮中选取方案,使得总和价值正好为m,如果有多种,方案为排列最小的那个. 可以把硬币看成w=v(即容量=价值)的…
题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805402305150976 题意: n个硬币,每一个有一个特有的价值,一个硬币只有一个,要求选取一些硬币使得他们的价值刚好是m 输出字典序最小的方案. 思路: 最近好久没有刷题了连PAT都好久没动了这样不行啊.连背包都有点不大会了.赶紧把PAT30分的刷完去刷洛谷了. 硬币是一个weight和value相同的物品,背包的容量就是m 问题转换成尽量让包中的价值大,背…
https://pintia.cn/problem-sets/994805342720868352/problems/994805402305150976 Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of…
01背包路径输出. 保证字典序最小:从大到小做背包. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<algorithm> using namespace std; +;…
题意: 输入两个正整数N和M(N<=10000,M<=10000),接着输入N个正整数.输出最小的序列满足序列和为M. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]; ][]; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n,m…
题目如下: Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special requirement of the paym…