POJ 1753 Flip Game(bfs+位压缩运算)】的更多相关文章

Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 p…
http://poj.org/problem?id=1753 题意:一个4*4的棋盘,只有黑和白两种棋子,每次翻转一个棋子,并且其四周的棋子也跟着翻转,求棋盘全为黑或全为白时所需的最少翻转次数. 思路:暴力枚举. 一共16个棋子,所以可以用二进制来存储.后来看了一下别人的代码,发现居然可以用异或运算来计算翻转情况,方便了不少. #include<iostream> #include<cstdio> #include<cstring> #include<queue&…
http://poj.org/problem?id=2965 题意: 一个4*4的矩形,有'+'和'-'两种符号,每次可以转换一个坐标的符号,同时该列和该行上的其他符号也要随之改变.最少需要几次才能全部变成'-'. 思路: 这道题和黑白棋那道题目差不多,唯一的差别就是需要记录一下路径. 我是用BFS来做的,用二进制来存储.翻转时用位运算的异或比较方便,可以看一下我的这篇博客(http://www.cnblogs.com/zyb993963526/p/6347741.html),上面写的比较清楚.…
题目地址:http://poj.org/problem?id=1753 /* 这题几乎和POJ 2965一样,DFS函数都不用修改 只要修改一下change规则... 注意:是否初始已经ok了要先判断 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <cmath> #include <string> #i…
Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37427   Accepted: 16288 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…
Description Flip game squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 pieces, thus changing the color of their upper side from black to white a…
Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 45691   Accepted: 19590 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…
题目网址:http://poj.org/problem?id=1753 题目: Flip Game Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying ei…
题目:http://poj.org/problem?id=1753 因为粗心错了好多次……,尤其是把1<<15当成了65535: 参考博客:http://www.cnblogs.com/kuangbin/archive/2011/07/30/2121677.html 主要思想: 1.如果用一个4*4的数组存储每一种状态,不但存储空间很大,而且在穷举状态时也不方便记录.因为每一颗棋子都只有两种状态,所以可以用二进制0和1表示每一个棋子的状态,则棋盘的状态就可以用一个16位的整数唯一标识.而翻转的…
题目链接 http://poj.org/problem?id=1753 题意 一个棋盘上有16个格子,按4×4排列,每个格子有两面,两面的颜色分别为黑色和白色,游戏的每一轮选择一个格子翻动,翻动该格子意味着将该格子及其上下左右格子(如果存在的话)的黑面朝上变成白面朝上,反之亦然,游戏的目标是格子全部黑面朝上或者全部白面朝上.输入棋盘的初始状态,求最少经过多少轮可以达到游戏的目标. 思路 求最少轮数,我会想到使用bfs来解决(dfs也可以解决),但使用bfs求解,如果每个状态都直接存储下当前棋盘的…