题意: 要求你给出每个前后缀相同的串的长度,比如: "alala"的前缀分别为{"a", "al", "ala", "alal", "alala"}, 后缀分别为{"a", "la", "ala", "lala", "alala"}. 其中有{"a", "al…

题目链接:http://poj.org/problem?id=2752 题意就是求出是已知s串的前缀的长度x,并且要求此前缀也是s串的后缀:求出所有的 x : Next[i]的含义是前i个元素的前缀和后缀的最大匹配: 所以本题就很简单了... #include<stdio.h> #include<iostream> #include<algorithm> #include<string.h> using namespace std; *1e5+; char…

next数组 1. 如果对于值k,已有p0 p1, ..., pk-1 = pj-k pj-k+1, ..., pj-1,相当于next[j] = k. 此意味着什么呢?究其本质,next[j] = k 代表p[j] 之前的模式串子串中,有长度为k 的相同前缀和后缀.有了这个next 数组,在KMP匹配中,当模式串中j 处的字符失配时,下一步用next[j]处的字符继续跟文本串匹配,相当于模式串向右移动j - next[j] 位. 举个例子,如下图,根据模式串“ABCDABD”的next 数组可…

文章转自 http://www.tuicool.com/articles/yayeIbe.这是我看到关于求next数组,解释最好的一篇文章!!!!!!! KMP的next数组求法是很不容易搞清楚的一部分,也是最重要的一部分.我这篇文章就以我自己的感悟来慢慢推导一下吧!保证你看完过后是知其然,也知其所以然. 如果你还不知道KMP是什么,请先阅读上面的链接,先搞懂KMP是要干什么. 下面我们就来说说KMP的next数组求法. KMP的next数组简单来说,假设有两个字符串,一个是待匹配的字符串str…

题目链接:https://vjudge.net/problem/POJ-2752 Seek the Name, Seek the Fame Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 21220   Accepted: 11065 Description The little cat is so famous, that many couples tramp over hill and dale to Byteland…

Seek the Name, Seek the Fame Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11831   Accepted: 5796 Description The little cat is so famous, that many couples tramp over hill and dale to Byteland, and asked the little cat to give names t…

Seek the Name, Seek the Fame Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11602   Accepted: 5680 Description The little cat is so famous, that many couples tramp over hill and dale to Byteland, and asked the little cat to give names t…

Seek the Name, Seek the Fame Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14106   Accepted: 7018 Description The little cat is so famous, that many couples tramp over hill and dale to Byteland, and asked the little cat to give names t…

Seek the Name, Seek the Fame Time Limit : 4000/2000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 12   Accepted Submission(s) : 7 Problem Description The little cat is so famous, that many couples tramp over hill an…

Seek the Name,Seek the Fame 过了个年,缓了这么多天终于开始刷题了,好颓废~(-.-)~ 我发现在家真的很难去学习,因为你还要陪父母,干活,做家务等等 但是还是不能浪费时间啊,要利用所有的时间去学习啊 [题目链接]Seek the Name,Seek the Fame [题目类型]KMP &题意: 给你一个字符串S.假如为ababcababababcabab 找出这个字符串中所有的前缀等于后缀的子串,输出它们的长度. 第一个为a,最后一个为b,所以1不行. 前两个为ab…