http://acm.hdu.edu.cn/showproblem.php?pid=4969 Guizeyanhua要去追一个女孩,女孩在以Guizeyanhua为圆心,半径为R的圆上匀速运动,女孩的速度为v1,Guizeyanhua的速度为v2,半径为R,Guizeyanhua腿疼只能跑距离D.现在Guizeyanhua要去追女孩,前提条件是女孩,Guizeyanhua,圆心必须保持共线. 直接上官方题解: #include <iostream> #include <stdio.h&g…

题目链接:hdu 4969 Just a Joke 题目大意:Guizeyanhua要去追一个女孩,女孩在以Guizeyanhua为圆心,半径为R的圆上匀速运动,女孩的速度为v1,Guizeyanhua的速度为v2,半径为R,Guizeyanhua腿疼仅仅能跑距离D.如今Guizeyanhua要去追女孩,前提条件是女孩,Guizeyanhua,圆心必须保持共线. 解题思路:由于有三点要共线的条件,所以Guizeyanhua和女孩的线速度必须同样,所以有v1R=vxr(vx为Guizeyanhua…

HDU 4969 Just a Joke pid=4969" target="_blank" style="">题目链接 推公式,r′=dr/dt=vy=v22−v12r2/R2−−−−−−−−−−−−√,可得积分公式为 ∫R0y=1/v22−v12x2/R2−−−−−−−−−−−−−√,利用三角换元去化简就可以 代码: #include <cstdio> #include <cstring> #include <cma…

题目链接:https://vjudge.net/problem/HDU-4969#author=0 题意:一个人在圆心以V2速度追赶一个以V1的速度进行圆周运动,问在圆心的人能否在不超过D的距离追上他,要求在追赶的过程中圆心和他们两个人三点共线. 题解:https://blog.csdn.net/weixin_30249203/article/details/96771264 1 #include<bits/stdc++.h> 2 using namespace std; 3 int main…

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2677    Accepted Submission(s): 1208 Problem Description Math is important!! Many students failed in 2+2’s mathematical test, so let's AC this pro…

题目:题目链接 思路:纯高等数学问题,不过不是很好积分,具体积分思路及过程参考大佬博客——https://blog.csdn.net/danliwoo/article/details/53002695 AC代码: #include <iostream> #include <cstdio> #include <algorithm> #include <cmath> #include <iomanip> using namespace std; #d…

physics 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5826 Description There are n balls on a smooth horizontal straight track. The track can be considered to be a number line. The balls can be considered to be particles with the same mass. At the…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=2493 题意:给你一个圆锥,水平放置,圆锥中心轴与地面平行,将圆锥装满水,在圆锥某一表面开一个小洞,流出来水的体积为V,给你地面直径D,高H,让你求小洞里地面的距离.(保证距离大于等于半径,小于等于直径) 题解:因为流出来水的那部分是一个不规则形状(相当于将圆锥水平切开,截面是一个三角形),我们可以二分答案下降高度r,现在关键是求体积. 然后通过一系列很复杂的积分运算,得出结果: 记得最后求出来的答案要…

/* hdu 1724 Ellipse simpson积分 求椭圆的部分面积 simpson积分法 http://zh.wikipedia.org/zh-tw/%E8%BE%9B%E6%99%AE%E6%A3%AE%E7%A7%AF%E5%88%86%E6%B3%95 */ #include<stdio.h> #include<math.h> const double eps=1e-8; inline double jue(double a) { return a>0?a:-…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5954 Problem DescriptionYou have got a cylindrical cup. Its bottom diameter is 2 units and its height is 2 units as well.The height of liquid level in the cup is d (0 ≤ d ≤ 2). When you incline the cup t…