写下这道题的原因很简单= =,因为这一题的状态转移方程不好找,另一方面,我看到很多针对这一题写的解题报告都把累加状态说得模棱两可,甚至直接说成了一个单一状态,弄得本是菜鸟的我硬生生折磨了一上午画了几个10*10的表才想出来(各种表思路还不一样= =||) 题意:对整数N(N<250)进行划分,划分成单峰回文序列,题目给出K组N,然后求出相应总序列数目. 例如: 1: (1) 2: (2), (1 1) 3: (3), (1 1 1) 4: (4), (1 2 1), (2 2), (1 1 1…

UNIMODAL PALINDROMIC DECOMPOSITIONS Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5430   Accepted: 2641 Description A sequence of positive integers is Palindromic if it reads the same forward and backward. For example: 23 11 15 1 37 37…

dp #include <cstdio> #include <cstring> #include <algorithm> using namespace std; #define maxn 252 int n; long long f[maxn][maxn]; //f[sum][last value] long long ans[maxn]; void init() { memset(f, , sizeof(f)); ; i < maxn; i++) f[][i]…

转自https://www.luogu.org/blog/cccx2016/dp50-ti-ti-hao dp50题: poj1014 poj1015 poj1018 poj1036 poj1038 poj1050 poj1088 poj1093 poj1156 poj1157 poj1159 poj1160 poj1163 poj1170 poj1191 poj1221 poj1338 poj1458 poj1579 poj1631 poj1651 poj1661 poj1664 poj167…