hdu 5120 Intersection 圆环面积交】的更多相关文章

Intersection Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5120 Description Matt is a big fan of logo design. Recently he falls in love with logo made up by rings. The following figures are some famous examples…
Problem Description Matt is a big fan of logo design. Recently he falls in love with logo made up by rings. The following figures are some famous examples you may know. A ring is a 2-D figure bounded by two circles sharing the common center. The radi…
Intersection Time Limit: 4000/4000 MS (Java/Others) Memory Limit: 512000/512000 K (Java/Others) Total Submission(s): 602 Accepted Submission(s): 247 Problem Description Matt is a big fan of logo design. Recently he falls in love with logo made up by…
题意:给定两个圆环,求两个圆环的面积交. 析:很容易知道,圆环面积交就是,大圆与大圆面积交 - 大圆和小圆面积交 - 小圆和大圆面积交 + 小圆和小圆面积交. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #includ…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5120 A ring is a 2-D figure bounded by two circles sharing the common center. The radius for these circles are denoted by r and R (r < R). For more details, refer to the gray part in the illustration bel…
Intersection Time Limit: 4000/4000 MS (Java/Others)    Memory Limit: 512000/512000 K (Java/Others) Problem Description Matt is a big fan of logo design. Recently he falls in love with logo made up by rings. The following figures are some famous examp…
Matt is a big fan of logo design. Recently he falls in love with logo made up by rings. The following figures are some famous examples you may know.A ring is a 2-D figure bounded by two circles sharing the common center. The radius for these circles…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5120 解题报告:给你两个完全相同的圆环,要你求这两个圆环相交的部分面积是多少? 题意看了好久没懂.圆环由一个大圆里面套一个小圆,中间部分就是圆环,两圆环相交面积 = 大圆相交的面积 - 2*大圆与小圆相交的面积 + 小圆与小圆相交的面积. 也就是说,这题就可以化为求两个圆的相交的面积了.可以利用两个圆的方程,求出圆的交点所在的直线,然后求出圆心到这条直线的距离,就可以求出两个圆对应的扇形的圆心角是多…
题意:给定两个圆环,求两个圆环相交的面积. 思路:由于圆心和半径不一样,分了好多种情况,后来发现只要把两个圆相交的函数写好之后就不需要那么复杂了.两个圆相交的面积的模板如下: double area_of_overlap(point c1, double r1, point c2, double r2) { double d = dist(c1, c2); ) ; ) { double r = min(r1, r2); return PI * r * r; } double x = (d * d…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5120 题目: 题意: 求两个圆环相交的面积. 思路: 两个大圆面积交-2×大圆与小圆面积交+两小圆面积交. 代码实现如下: #include <set> #include <map> #include <deque> #include <ctime> #include <stack> #include <cmath> #include…