P2935 [USACO09JAN]最好的地方Best Spot 题目描述 Bessie, always wishing to optimize her life, has realized that she really enjoys visiting F (1 <= F <= P) favorite pastures F_i of the P (1 <= P <= 500; 1 <= F_i <= P) total pastures (conveniently nu…

P2935 [USACO09JAN]最好的地方Best Spot Floyd的水题(黄题) 海星. 这可能是我第一道发的Floyd的博客 inline void Floyd(){ ;k<=n;k++) ;i<=n;i++) ;j<=n;j++) dis[i][j]=Min(dis[i][j],dis[i][k]+dis[k][j]); } 这个是Floyd的算法 很简单就三行 仅此而已 但是 这个是一种方法 简单的说 Floyd是一种DP 求最短路(最长路)反正比spfa啥的好打 最关键…

OJ题号:洛谷2935 思路:Floyd #pragma GCC optimize ("O3") #include<cstdio> #include<cctype> #define inf 0x7fffffff>>1 inline int min(const int a,const int b) { return a<b?a:b; } inline int getint() { int ch; while(!isdigit(ch=getchar…

题目描述 Bessie, always wishing to optimize her life, has realized that she really enjoys visiting F (1 <= F <= P) favorite pastures F_i of the P (1 <= P <= 500; 1 <= F_i <= P) total pastures (conveniently numbered 1..P) that compose Farmer…

Luogu P2935 最好的地方Best Spot 这道题就是一道近乎裸的Floyd,因为数据很小,所以用领接表存图就可以了. #include<bits/stdc++.h> #define INF 0x3fffffff #define N 510 using namespace std; int p,f,c,mmin=INF,sum,ans; int like[N],e[N][N]; void Read() { scanf("%d%d%d",&p,&f,…

Black Spot Time limit: 1.0 secondMemory limit: 64 MB Bootstrap: Jones's terrible leviathan will find you and drag the Pearl back to the depths and you along with it. Jack: Any idea when Jones might release said terrible beastie? Bootstrap: I already…

spot 5监督分类RGB：412 ALOS分类波段RGB：432…

Spot light on UNIX 安装没什么问题 Spot light on Oracle  必须安装32位的客户端,不然搞死你 两者的界面都是吊炸天啊…

3394: [Usaco2009 Jan]Best Spot 最佳牧场 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 11  Solved: 9[Submit][Status] Description   Input 第1行输入三个整数P,F C.之后F行每行输入一个整数表示一个贝茜喜欢的牧场．之后C行每行输入三个整数ai,bi,Ti,描述一条路． Output 一个整数,满足题目要求的最佳牧场．如果有多个答案,输出编号最小的 Sample Inp…

 The Spot Game  The game of Spot is played on an NxN board as shown below for N = 4. During the game, alternate players may either place a black counter (spot) in an empty square or remove one from the board, thus producing a variety of patterns. If…