地址 https://leetcode-cn.com/problems/maximum-score-words-formed-by-letters/ 题目描述你将会得到一份单词表 words,一个字母表 letters (可能会有重复字母),以及每个字母对应的得分情况表 score. 请你帮忙计算玩家在单词拼写游戏中所能获得的「最高得分」:能够由 letters 里的字母拼写出的 任意 属于 words 单词子集中,分数最高的单词集合的得分. 单词拼写游戏的规则概述如下: 玩家需要用字母表 le…

题目描述: 方法:穷举暴力 class Solution: def maxScoreWords(self, words: List[str], letters: List[str], score: List[int]) -> int: from collections import Counter n = len(words) v = lambda c: ord(c) - ord('a') words = [Counter(v(c) for c in w) for w in words] sco…

This is a follow up of Shortest Word Distance. The only difference is now you are given the list of words and your method will be called repeatedly many times with different parameters. How would you optimize it? Design a class which receives a list…

This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as word2. Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. word1 and word2 may be…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

We are given N different types of stickers. Each sticker has a lowercase English word on it. You would like to spell out the given target string by cutting individual letters from your collection of stickers and rearranging them. You can use each sti…

Find the minimum length word from a given dictionary words, which has all the letters from the string licensePlate. Such a word is said to complete the given string licensePlate Here, for letters we ignore case. For example, "P" on the licensePl…

Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words.  It is guaranteed there is at least one word that isn't banned, and that the answer is unique. Words in the list of banned words are…

Design a class which receives a list of words in the constructor, and implements a method that takes two words word1 and word2 and return the shortest distance between these two words in the list. Your method will be called repeatedly many times with…

Easy! 题目描述: 给定一个仅包含大小写字母和空格 ' ' 的字符串,返回其最后一个单词的长度. 如果不存在最后一个单词,请返回 0 . 说明:一个单词是指由字母组成,但不包含任何空格的字符串. 示例: 输入: "Hello World" 输出: 5 解题思路: 这道题难度不是很大.先对输入字符串做预处理,去掉开头和结尾的空格,然后用一个计数器来累计非空格的字符串的长度,遇到空格则将计数器清零. C++解法一: class Solution { public: int length…

公众号:爱写bug(ID:icodebugs) 给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序. Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. 示例 1: 输入: "Let's take LeetCode co…

An abbreviation of a word follows the form <first letter><number><last letter>. Below are some examples of word abbreviations: a) it --> it (no abbreviation) 1 b) d|o|g --> d1g 1 1 1 1---5----0----5--8 c) i|nternationalizatio|n --&…

162. 寻找峰值 162. Find Peak Element 题目描述 峰值元素是指其值大于左右相邻值的元素. 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引. 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可. 你可以假设 nums[-1] = nums[n] = -∞. 每日一算法2019/6/1Day 29LeetCode162. Find Peak Element 示例 1: 输入: nums = [1,2,3,1]…

Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. For example,Assume that words = ["practice", "makes", "perfect", "coding", "makes"]. G…

A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…

A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the pea…

一.题目链接: https://leetcode.com/problems/find-peak-element/ 二.题目大意: 给定一个长度为N的一维数组,数组是无序的,要求找到数组中的极大值(或局部最大值),并返回该极大值的下标,并假设 nums[-1] = nums[n] = -∞.:当某元素同时大于它两边的元素时,则该元素是数组中的一个极大值,数组中若存在多个极大值,则返回任意一个即可. 算法的时间复杂度要求为log级别. 三.题解: 这个问题的最直观的解法,就是遍历一遍数组,然后判断每…

Hard! 题目描述: 给定一个字符串 s 和一些长度相同的单词 words.在 s 中找出可以恰好串联 words 中所有单词的子串的起始位置. 注意子串要与 words 中的单词完全匹配,中间不能有其他字符,但不需要考虑 words 中单词串联的顺序. 示例 1: 输入: s = "barfoothefoobarman", words = ["foo","bar"] 输出: [0,9] 解释: 从索引 0 和 9 开始的子串分别是 "…

Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. Example…

给定一种 pattern(模式) 和一个字符串 str ,判断 str 是否遵循相同的模式. 这里的遵循指完全匹配,例如, pattern 里的每个字母和字符串 str 中的每个非空单词之间存在着双向连接的对应模式. 示例1: 输入: pattern = "abba", str = "dog cat cat dog" 输出: true 示例 2: 输入:pattern = "abba", str = "dog cat cat fish&…

Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space char…

A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…

[题目描述] 给定一个仅包含大小写字母和空格 ' ' 的字符串,返回其最后一个单词的长度. 如果不存在最后一个单词,请返回 0 . 说明:一个单词是指由字母组成,但不包含任何空格的字符串. 示例: 输入: "Hello World"输出: 5 [解答] 解法一:利用python自带的函数 .rstrip() 可以去除字符串尾部的空格 再从后往前遍历,直至当前遇到空格,也就是s[i] == ' ' 的情况 class Solution: def lengthOfLastWord(self…

720. 词典中最长的单词 给出一个字符串数组words组成的一本英语词典.从中找出最长的一个单词,该单词是由words词典中其他单词逐步添加一个字母组成.若其中有多个可行的答案,则返回答案中字典序最小的单词. 若无答案,则返回空字符串. 示例 1: 输入: words = ["w","wo","wor","worl", "world"] 输出: "world" 解释: 单词"…

162. 寻找峰值 峰值元素是指其值大于左右相邻值的元素. 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引. 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可. 你可以假设 nums[-1] = nums[n] = -∞. 示例 1: 输入: nums = [1,2,3,1] 输出: 2 解释: 3 是峰值元素,你的函数应该返回其索引 2. 示例 2: 输入: nums = [1,2,1,3,5,6,4] 输出: 1 或 5 解…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3969 访问. 给定一个段落 (paragraph) 和一个禁用单词列表 (banned).返回出现次数最多,同时不在禁用列表中的单词.题目保证至少有一个词不在禁用列表中,而且答案唯一. 禁用列表中的单词用小写字母表示,不含标点符号.段落中的单词不区分大小写.答案都是小写字母. 输入: paragraph = "Bob hit a ball, the hit BA…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3927 访问. 给定一个仅包含大小写字母和空格 ' ' 的字符串,返回其最后一个单词的长度. 如果不存在最后一个单词,请返回 0 . 说明:一个单词是指由字母组成,但不包含任何空格的字符串. 输入: "Hello World" 输出: 5 Given a string s consists of upper/lower-case alphabets an…

5629. 重新格式化电话号码 模拟 注意一些细节,最后位置是否取值. class Solution { public: string reformatNumber(string number) { string s; for (auto c: number) if (c != ' ' && c != '-') s += c; string res; for (int i = 0; i < s.size();) { if ((int)s.size() - i > 4) res…

151. 翻转字符串里的单词 知识点:字符串:双指针 题目描述 给你一个字符串 s ,逐个翻转字符串中的所有 单词 . 单词 是由非空格字符组成的字符串.s 中使用至少一个空格将字符串中的 单词 分隔开. 请你返回一个翻转 s 中单词顺序并用单个空格相连的字符串. 说明: 输入字符串 s 可以在前面.后面或者单词间包含多余的空格. 翻转后单词间应当仅用一个空格分隔. 翻转后的字符串中不应包含额外的空格 示例 输入:s = "the sky is blue" 输出:"blue…

Problem: A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the pe…