Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路一: 之前我们有mergeTwoLists(ListNode l1, ListNode l2)方法,直接调用的话,需要k-1次调用,每次调用都需要产生一个ListNode[],空间开销很大.如果采用分治的思想,对相邻的两个ListNode进行mergeTwoLists,每次将规模减少一半,直到…

题目要求:Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Analysis The simplest solution is using PriorityQueue. The elements of the priority queue are ordered according to their natu…

题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 翻译 合并k个有序的链表 Hints Related Topics: LinkedList, Divide and Conquer, Heap Solution1:Divide and Conquer 参考 归并排序-维基百科 思路:分治,先分成两个子任务,然后递归子任务,最后回溯回来..这里就…

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.   采用优先队列priority_queue 把ListNode放入优先队列中,弹出最小指后,如果该ListNode有下一个元素,则把下一个元素放入到队列中     /** * Definition for singly-linked list. * stru…

题目描述: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路: 分治方法.将K个List不断地分解为前半部分和后半部分.分别进行两个List的合并.最后将合并的结果合并起来. 代码如下: /** * Definition for singly-linked list. * public class ListNode { * int val;…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题解: 归并思想. Solution 1 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {…

1 题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 2 思路 当时看到这个题目就想到的是归并排序.好吧,但是,具体代码写不出来.题目给的是数组:public ListNode mergeKLists(ListNode[] lists),我就想,怎么归并排序,然后返回一个已经排好的,再进行递归.想破脑袋没想出来. 原来,可以赋值给一个Array…

转载:https://leetcode.windliang.cc/leetCode-23-Merge-k-Sorted-Lists.html 描述 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input:[ 1->4->5, 1->3->4, 2->6]Output: 1->1->2->3…

题目链接: https://leetcode.com/problems/merge-k-sorted-lists/?tab=Description Problem: 给出k个有序的list, 将其进行合并得到一个有序的list   对于给出的ListNode[] lists ,可以进行两两合并.divide and conquer  将list分为前后两部分,对前半部分再次进行分半操作,对后半部分进行分半操作,然后将其进行合并操作. 合并操作也就是对两个list进行合并 合并操作可以采用递归算法…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 这道题让我们合并k个有序链表,最终合并出来的结果也必须是有序的,之前做过一道 M…

题目:Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题意:把k个排序成一个有序链表. 用优先队列先把k个链表遍历一遍把值存起来,在建一个新链表吧数从优先队列里一个个放进去,注意空指针的判断. /** * Definition for singly-linked list. * struct ListNode { * int val; * List…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 题意: 归并k个有序链表. 思路: 用一个最小堆minHeap,将所有链表的头结点放入 新建一个linkedl…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解法1: 采用递归的方法,不管合并几个,归根到底还是需要两两合并. 首先想到的是前两个先合并,然后再跟第三个合并,然后第四个....但是这种做法效率不高. 换个思路,采用分治法,对数量超过2的任务进行拆分,直到最后只有一个或两个链表再进行合并.代码如下: /** * Definition for si…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题意:对k个有序的链表进行归并排序.并分析其复杂度. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(N…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 要合并K个排好序的链表,我用的方法是用一个优先队列每次存K个元素在队列中,根据优…

题目: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 代码:oj测试通过 Runtime: 231 ms # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class S…

Merge k sorted linked lists and return it as one sorted list. 题意:把k个已经排好序的链表整合到一个链表中,并且这个链表是排了序的. 题解:这是一道经典好题,值得仔细一说. 有两种方法,假设每个链表的平均长度是n,那么这两种方法的时间复杂度都是O(nklogk). 方法一: 基本思路是:把k个链表开头的值排个序,每次取最小的一个值放到答案链表中,这次取完之后更新这个值为它后面的一个值.接着这么取一直到全部取完.那么每次更新之后怎么对当…

合并K个有序链表,并且作为一个有序链表的形式返回.分析并描述它的复杂度. 详见:https://leetcode.com/problems/merge-k-sorted-lists/description/ 实现语言:Java /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ cla…

/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ struct helper { ListNode *head; int len; helper(ListNode *h, int l) : head ( h ), len ( l ) {} }; class helper…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 23: Merge k Sorted Listshttps://oj.leetcode.com/problems/merge-k-sorted-lists/ Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ===Comments…

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Show Tags 参考资料: http://blog.csdn.net/linhuanmars/article/details/19899259. SOLUTION 1: 使用分治法.左右分别递归调用Merge K sorted List,然后再使用merg…

Question 23. Merge k Sorted Lists Solution 题目大意:合并链表数组(每个链表中的元素是有序的),要求合并后的链表也是有序的 思路:遍历链表数组,每次取最小节点 Java实现: public ListNode mergeKLists(ListNode[] lists) { ListNode preHead = new ListNode(0); ListNode minNode = getMinNode(lists); ListNode tmpNode =…

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题目意思: 合并K条已经排序的链表.分析时间复杂度. 解题思路: 很容易就想起之前学的合并两条链表的算法,这一题其实就是那个题目的扩展,变成合并K条了.我采用的方法就是迭代法. 如果只有一条,直接返回.如果只有两条,就只需要调用mergeTwo一下.如果超过两…

1. Merge Two Sorted Lists 题目链接 题目要求:  Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 这道题目题意是要将两个有序的链表合并为一个有序链表.为了编程方便,在程序中引入dummy节点.具体程序如下: /** * Definitio…

Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 依次拼接 复杂度 时间 O(N) 空间 O(1) 思路 该题就是简单的把两个链表的节点拼接起来,我们可以用一个Dummy头,将比较过后的节点接在这个Dummy头之后.最后…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相…

1. Merge Two Sorted Lists 我们先来看这个 问题: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 是的,这是一个非常简单链表操作问题.也许你只需要花几分种便能轻松写出代码. 2. Merge k Sorted Lists 我们现在来研究这…

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 两个方法: 方法1. 利用 STL 中的 multiset (根据结点内的值)自动对指针排序.空间 O(N), 时间 O(NlogN). (亦可用于 k 个无序链表).(AC: 164ms) /** * Definition for singly-linked…

leetcode-algorithms-23 Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 解法…