PAT 1074. Reversing Linked List (25)】的更多相关文章

Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L.  For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you must output 4→3→2→1→5→6. Input Specifica…
1074 Reversing Linked List (25 分)   Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must outp…
1074 Reversing Linked List (25)(25 分) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you mus…
题目 Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you must output 4→3→2→1→5→6. Input Specifi…
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<algorithm> using namespace std; +; struct Node { ]; ]; ]…
题意说的很清楚了,这种题的话,做的时候最好就是在纸上自己亲手模拟一下,清楚一下各个指针的情况, 这样写的时候就很清楚各个指针变量保存的是什么值. PS:一次AC哈哈,所以说自己动手在纸上画画还是很有好处的~ #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <queue> us…
题意: 输入链表头结点的地址(五位的字符串)和两个正整数N和K(N<=100000,K<=N),接着输入N行数据,每行包括结点的地址,结点的数据和下一个结点的地址.输出每K个结点局部反转的链表. trick: 测试点6包含一些不在起点这条链表上的结点. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; map<string,pair<i…
[程序思路] 先根据地址按顺序读入节点,入栈,当栈里的元素个数等于k时全部出栈,并按出栈顺序保存,最后若栈不为空,则全部出栈并按出栈的稀饭顺序保存,最后输出各节点 注意:输入的节点中有可能存在无用节点需要过滤,这里我使用map映射来实现过滤 [代码实现] #include<bits/stdc++.h> using namespace std; struct node{ int addrest,data,next; }t; int stk[100005]; int main(){ map<…
模拟题,注意当k == 1 与 k == n时情况 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include <map> using namespace std; const int N = 100005; struct Node { int pre; int value; int lat; }node[N]; int orde…
#include <cstdio> #include <cstdlib> #include <iostream> #include <unordered_map> using namespace std; class Node { public: int data; int next; Node() : data(), next() {} Node(int d, int n):data(d), next(n){} }; int reverse_help(in…