Given a list of words, we may encode it by writing a reference string S and a list of indexes A. For example, if the list of words is ["time", "me", "bell"], we can write it as S = "time#bell#" and indexes = [0, 2,…

题目如下: 解题思路:本题考查就是找出一个单词是不是另外一个单词的后缀,如果是的话,就可以Short Encode.所以,我们可以把words中每个单词倒置后排序,然后遍历数组,每个元素只要和其后面相邻的元素比较,如果是后缀则被Short Encode,否则不行. 代码如下: class Solution(object): def minimumLengthEncoding(self, words): """ :type words: List[str] :rtype: in…

Given a list of words, we may encode it by writing a reference string S and a list of indexes A. For example, if the list of words is ["time", "me", "bell"], we can write it as S = "time#bell#" and indexes = [0, 2,…

Given a list of words, we may encode it by writing a reference string S and a list of indexes A. For example, if the list of words is ["time", "me", "bell"], we can write it as S = "time#bell#" and indexes = [0, 2,…

2018-07-02 09:48:48 问题描述: 问题求解: 方法一.问题给了规模n = 2000,也就是说用BF在O(n^2)的时间复杂度可以过,因此,第一个方法就是BF,但是需要注意的是这里已经非常擦边了,所以需要对常数项进行优化. public int minimumLengthEncoding(String[] words) { boolean[] flag = new boolean[words.length]; int[] lens = new int[words.length];…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode-cn.com/problems/short-encoding-of-words/ 题目描述 单词数组 words 的 有效编码 由任意助记字符串 s 和下标数组 indices 组成,且满足: words.length == indices.length 助记字符串 s 以 '#' 字符结尾 对于每个下标 indices[i] ,s 的一个从…

RSA public key ASN.1 encode is defined in PKCS#1 as follows: RSAPublicKey :: = SEQUENCE  {     modulus    INTEGER,  -- n     publicExponent    INTEGER  -- e }     In a DER encoded certificate the SEQUENCE is encoded again as BIT STRING type, that is,…

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Contest 81 (2018年11月8日,周四,凌晨) 链接:https://leetcode.com/contest/weekly-contest-81 比赛情况记录:结果:3/4, ranking: 440/2797.这次题目似乎比较简单,因为我比赛的时候前三题全做出来了(1:12:39),然后第四题有思路,正在写,没写完,比赛完了写完提交也对了. [821]Shortest Distance to a Character(第一题 4分) 给了一个单词(字符串)s,和单词中的任意一个字母…