首先我们先来回忆一下小学一年级就学过的知识:任何一个偶数都是 \(2\) 的倍数,那么我们就可以分成两种情况考虑:奇数和偶数. 对于偶数,我们可以直接将其输出,因为它必定能被 \(2\) 与它自己整除(第一段中有提到). 对于奇数,我们需要将它变成一个偶数,并且改变后的偶数还要被 \(a\) 本身整除,因此,我们可以直接将 \(a \times 2\),这样就是一个既可以被 \(2\) 整除又可以被 \(a\) 本身整除的数了. 通过上面的分析,我们将其整理后,思路如下. 如果 \(a\) 是偶…

[POJ2356]Find a multiple Description -The input contains N natural (i.e. positive integer) numbers ( N <= 10000 ). Each of that numbers is not greater than 15000. This numbers are not necessarily different (so it may happen that two or more of them w…

Description Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no mo…

求一组数据的最小公倍数. 先求公约数在求公倍数.利用公倍数,连续求全部数的公倍数就能够了. #include <stdio.h> int GCD(int a, int b) { return b? GCD(b, a%b) : a; } inline int LCM(int a, int b) { return a / GCD(a, b) * b; } int main() { int T, m, a, b; scanf("%d", &T); while (T--)…

求n个数的最小公倍数. Input输入包含多个测试实例,每个测试实例的开始是一个正整数n,然后是n个正整数. Output为每组测试数据输出它们的最小公倍数,每个测试实例的输出占一行.你可以假设最后的输出是一个32位的整数.Sample Input 2 4 6 3 2 5 7 Sample Output 12 70 求最小公倍数算法: 最小公倍数=两整数的乘积÷最大公约数 __gcd(int,int)函数   返回值即是这两个数的最大公约数,使用时需要包含头文件#include<algorith…

Find a multiple Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7192   Accepted: 3138   Special Judge Description The input contains N natural (i.e. positive integer) numbers ( N <= 10000 ). Each of that numbers is not greater than 15000…

原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4-ii-call-multiple-times/ 题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns…

http://cdn.ac.nbutoj.com/Problem/view.xhtml?id=1541 When rain, nocLyt discovered a magical phenomenon that the rainwater always flow to the low-lying place. 我以后都在题解里放一小段题目,让人更容易搜到,有没有很有想法!(咦这样好像放全部的题目更容易被搜到啊)(不过那样好像比较乱啊) [] Rainwater 时间限制: ms 内存限制: K…

Find The Multiple Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 21851 Accepted: 8984 Special Judge Description Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only t…

题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the func…