[PAT] A1021 Deepest Root】的更多相关文章

A graph which is connected and acyclic can be considered a tree. The hight of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: Ea…
[题目大意] 给出n个结点和n-1条边,问它们能否形成一棵n个结点的树,如果能,从中选出结点作为树根,使整棵树的高度最大.输出所有满足要求的可以作为树根的结点. [思路] 方法一:模拟. 1 连通.边数为n-1的图一定是一棵树.因此先判断连通图个数(用DFS遍历图,从而计算连通图个数),等于1则能形成一棵树. 2 遍历每一个节点,假设它为根节点构造一棵树. 方法二: 1 由于连通.边数为n-1的图一定是一棵树,因此需要判断给定数据是否能使图连通.2 确定图连通后,则确定了树,选择合适根结点使树高…
A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: E…
题目 A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification…
A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: E…
1021 Deepest Root (25)(25 分) A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest…
1021 Deepest Root (25)(25 分)A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest…
#include <cstdio> #include <cstdlib> #include <vector> using namespace std; class Node { public: vector<int> adj; bool visited; Node() : visited(false) {} }; void reset_nodes(vector<Node>& nodes) { int len = nodes.size();…
Source: PAT A1021 Deepest Root (25 分) Description: A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root…
PAT甲级1021. Deepest Root 题意: 连接和非循环的图可以被认为是一棵树.树的高度取决于所选的根.现在你应该找到导致最高树的根.这样的根称为最深根. 输入规格: 每个输入文件包含一个测试用例.对于每种情况, 第一行包含正整数N(<= 10000),它是节点的数量,因此节点从1到N编号.然后按N-1行,每个都通过给定两个相邻节点的数字来描述一个边. 输出规格: 对于每个测试用例,打印一行中最深的根.如果这样的根不是唯一的, 打印他们的数字增加的顺序.在给定的图形不是树的情况下,打…