题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The lef subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys grea…

题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys gre…

题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The lef subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys grea…

1043 Is It a Binary Search Tree (25 分)   A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a…

1043 Is It a Binary Search Tree(25 分) A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a nod…

https://pintia.cn/problem-sets/994805342720868352/problems/994805440976633856 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than th…

题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys gre…

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greate…

简单题.构造出二叉搜索树,然后check一下. #include<stdio.h> #include<algorithm> using namespace std; +; struct Node { int left; int right; int val; } s[maxn]; int n; int a[maxn]; int ans[maxn],tot; int h[maxn]; int k; void dfs(int x) { ans[k++]=s[x].val; ) dfs(…

预处理每个节点左子树有多少个点. 然后确定值得时候递归下去就可以了. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; struct Node { int…