Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string s, sort it in decreasing order based on the frequency of the characters. The frequency of a character is the number of times it appears in the string. Return the sorted string. If there are multiple answers, return any of them. 考察了map的…

［抄题］: Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and '…

题目: Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'…

https://leetcode.com/problems/sort-characters-by-frequency/ Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 优先级队列 排序 日期 题目地址:https://leetcode.com/problems/sort-characters-by-frequency/description/ 题目描述 Given a string, sort it in decreasing order based on the frequency of character…

给定一个字符串,请将字符串里的字符按照出现的频率降序排列.示例 1:输入:"tree"输出:"eert"解释:'e'出现两次,'r'和't'都只出现一次.因此'e'必须出现在'r'和't'之前.此外,"eetr"也是一个有效的答案. 示例 2:输入:"cccaaa"输出:"cccaaa"解释:'c'和'a'都出现三次.此外,"aaaccc"也是有效的答案.注意"cacaca&q…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c" and its frequency is 2. Now, given st…

http://www.geeksforgeeks.org/sort-elements-by-frequency-set-2/ #include <iostream> #include <vector> #include <algorithm> #include <queue> #include <stack> #include <string> #include <fstream> #include <map>…

［抄题］: 给出一个字符串.找到字符串中第一个不重复的字符然后返回它的下标.如果不存在这样的字符,返回 -1. 给出字符串 s = "lintcode",返回 0.给出字符串 s = "lovelintcode",返回 2. [暴力解法]: 时间分析: 空间分析: ［思维问题］: ［一句话思路］: 用cnt[256]数组存储即可 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 不用break,…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

2.Add Two Numbers 原题链接https://leetcode.com/problems/add-two-numbers/ AC解: public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int sum = 0; ListNode head = new ListNode(0); ListNode dummy = new ListNode(0); ListNode flag = dummy; dummy.next = he…

299. Bulls and Cows 思路:抽屉法,放进secrets,拿出guess,最终cows = cows - bulls public String getHint(String secret, String guess) { int bulls = 0; int cows = 0; int[] numbers = new int[10]; for(int i = 0; i < secret.length(); i++){ if(secret.charAt(i) == guess.c…

1. Two Sum https://leetcode.com/problems/two-sum/description/ 不使用额外空间需要n*n的复杂度 class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { ;i<nums.size()-;i++){ ;j<nums.size();j++){ if(nums[i] + nums[j] == target){ v…

2018-05-03 刷了牛客网的题目:总结思路(总的思路跟数学一样就是化简和转化) 具体启发点: 1.对数据进行预处理排序的思想:比如8皇后问题 2.对一个数组元素进行比较的操作,如果复杂,可以试试倒过来,从最后一个元素往前面想. 3.动态规划,分治法. 4.超复杂的循环最好的方法是while 1:这种写法.(因为他最大程度保证了灵活性,比如leecode的283题) leecode习题: 主要是目前在学习 玩转算法面试 leetcode 这个课程,他把leecode的题目做分类,将例题,留习…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

堆基础 堆(Heap)是具有这样性质的数据结构:1/完全二叉树 2/所有节点的值大于等于(或小于等于)子节点的值: 图片来源:这里 堆可以用数组存储,插入.删除会触发节点shift_down.shift_up操作,时间复杂度O(logn). 堆是优先级队列(Priority queue)的底层数据结构,较常使用优先级队列而非直接使用堆处理问题.利用堆的性质可以方便地获取极值,例如 LeetCode 题目 215. Kth Largest Element in an Array,时间复杂度O(nl…

Hash Table基础 哈希表(Hash Table)是常用的数据结构,其运用哈希函数(hash function)实现映射,内部使用开放定址.拉链法等方式解决哈希冲突,使得读写时间复杂度平均为O(1). HashMap(std::unordered_map).HashSet(std::unordered_set)的原理与Hash Table一样,它们的用途广泛.用法灵活,接下来侧重于介绍它们的应用. 相关LeetCode题: 706. Design HashMap  题解  705. Des…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…