B2 - TV Subscriptions (Hard Version)】的更多相关文章

链接: https://codeforces.com/contest/1247/problem/B2 题意: The only difference between easy and hard versions is constraints. The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequen…
题目连接:https://codeforces.com/contest/1247/problem/B2 题解:双指针,,一个头,一个尾,头部进入,尾部退出,一开始先记录1到k,并记录每个数字出现的次数,然后在头进尾出,依次判断. #include<bits/stdc++.h> using namespace std; ; map<int ,int >mp; int arr[N]; void solve(){ mp.clear(); int n,m,k; cin>>n&g…
CF1225B2 TV Subscriptions (Hard Version) 洛谷评测传送门 题目描述 The only difference between easy and hard versions is constraints. The BerTV channel every day broadcasts one episode of one of the kk TV shows. You know the schedule for the next nn days: a seque…
CF1225B1 TV Subscriptions (Easy Version) 洛谷评测传送门 题目描述 The only difference between easy and hard versions is constraints. The BerTV channel every day broadcasts one episode of one of the kk TV shows. You know the schedule for the next nn days: a seque…
B2. TV Subscriptions (Hard Version) The only difference between easy and hard versions is constraints. The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a1,a…
[CodeForces-1225B] TV Subscriptions [贪心][尺取法] 标签: 题解 codeforces题解 尺取法 题目描述 Time limit 2000 ms Memory limit 262144 kB Source Technocup 2020 - Elimination Round 2 Tags implementation  two pointers  *1300 Site https://codeforces.com/problemset/problem/1…
B2. Character Swap (Hard Version) This problem is different from the easy version. In this version Ujan makes at most 2…
time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output The only difference between easy and hard versions is constraints. The BerTV channel every day broadcasts one episode of one of the k TV sho…
题目链接:http://codeforces.com/problemset/problem/1249/B2 思路:用并查集模拟链表,把关系串联起来,如果成环,则满足题意.之后再用并查集合并一个链,一个链代表 一个集合,一个集合有共同的祖先,一个集合答案相同,则输出答案时候只需要输出该元素属于哪一个集合,那个集合有几个元素 就可以了. #include <stdio.h> #include <iostream> using namespace std; ; int fa[N]; in…
链接: https://codeforces.com/contest/1234/problem/B2 题意: The only difference between easy and hard versions are constraints on n and k. You are messaging in one of the popular social networks via your smartphone. Your smartphone can show at most k most…