ZOJ 3203 Light Bulb(数学对勾函数)】的更多相关文章

Light Bulb Time Limit: 1 Second      Memory Limit: 32768 KB Compared to wildleopard's wealthiness, his brother mildleopard is rather poor. His house is narrow and he has only one light bulb in his house. Every night, he is wandering in his incommodio…
B - Light Bulb Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Submit Status Practice ZOJ 3203 Description Compared to wildleopard's wealthiness, his brother mildleopard is rather poor. His house is narrow and he has only o…
Light Bulb Problem's Link:   http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3203 Mean: 灯的位置固定,而人的位置不固定,求人的影子的最大长度. analyse: 当灯.人的头部.右墙角在同一条直线上时,此时人的影子全部在地板上:当人继续往右走的时候,影子分为地板上的和墙上的,由此可见这是一个先增后减的凸函数,三分取最大值即可. double cal(Type a) { return…
Light Bulb Time Limit: 1 Second      Memory Limit: 32768 KB Compared to wildleopard's wealthiness, his brother mildleopard is rather poor. His house is narrow and he has only one light bulb in his house. Every night, he is wandering in his incommodio…
如果L全在地面上: 输出 h * D / H 如果L全在墙上: 输出 h 否则: (D - X ) / X = Y / (H - h) L = D - X + h - Y 然后对L求导即可 #include <stdio.h> #include <string.h> #include <math.h> #include <algorithm> using namespace std; int main(){ double H,h,D,x,y,x0; int…
Light Bulb Time Limit: 1 Second      Memory Limit: 32768 KB Compared to wildleopard's wealthiness, his brother mildleopard is rather poor. His house is narrow and he has only one light bulb in his house. Every night, he is wandering in his incommodio…
Compared to wildleopard's wealthiness, his brother mildleopard is rather poor. His house is narrow and he has only one light bulb in his house. Every night, he is wandering in his incommodious house, thinking of how to earn more money. One day, he fo…
Time Limit: 1 Second      Memory Limit: 32768 KB Compared to wildleopard's wealthiness, his brother mildleopard is rather poor. His house is narrow and he has only one light bulb in his house. Every night, he is wandering in his incommodious house, t…
链接:传送门 题意: 求影子长度 L 的最大值 思路:如果 x = 0 ,即影子到达右下角时,如果人继续向后走,那么影子一定是缩短的,所以不考虑这种情况.根据图中的辅助线外加相似三角形定理可以得到 L = D * (h-x)/(H-x) + x , 再经过一些变形后可知这个 L = D * ( H - h )/( x - H ) + ( x - H ) + H + D ,明显的对号函数在左侧的图像,所以一定是个 凸函数 ,用三分求出极值即可 /**************************…
题意:灯离地面的高度为$H$,人的身高为$h$,灯离墙的距离为$D$,人站在不同位置,影子的长度不一样,求出影子的最长长度. 思路:设人离灯的距离为$x$,当人走到距离灯长度为$L$时,人在墙上的影子消失,此时人再往前走,影子的长度必然会减小,此时的$L$就为三分的左边界,右边界为$R=D$,由形似三角形可以推导出$L=D-\frac{h*D}{H}$,影子的长度 $$f(x)=D-x+H-\frac{(H-h)*D}{x},x\in [D-\frac{h*D}{H},D]$$ 在区间$[D-\…